Given:
It is given that,
PQ ⊥ PS and
∠QPR = 7x-9
∠RPS = 4x+22
To find the value of ∠QPR.
Formula
As per the given problem PR lies between PQ and PS,
So,
∠QPR+∠RPS = 90°
Now,
Putting the values of ∠RPS and ∠QPR we get,
or,
or,
or,
or,
Substituting the value of in ∠QPR we get,
∠QPR =
or, ∠QPR =
Hence,
The value of ∠QPR is 40°.
Answer:
an equation of a line
Step-by-step explanation:
This is an equation of a line. Lets walk through it.
y=1/3x+2
This is to find out what the Y coordinate would be when X is plugged in. So, if x was 6, you would take 1/3 of 6 to get 2, and add 2. The y intercept would be 4, since y=1/3(6)+2, y=2+2, y=4
Y=1/3x+2
This is what the slope is. If the slope is negative (ie. -3/4) the greater the x intercept the lower the y will be. (so if I had x=4 for a slope of -3/4, that would be y=-3/4(4)+2, y=-3+2, y=-1) But if the slope is positive (ie. 1/3) the greater the x value the greater the y value as well. (see graph attached below for positive)
Y=1/3x+2
This is the Y intercept. (This is NOT the y coordinate. This is only the coordinate of y if x=0) This number tells you where the Y intercept is. If it adds, the y intercept is positive. If it subtracts, the y intercept is negative.
Sorry if these explainations dont make sense. But, here is the graph for y=1/3x+2
