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Anna35 [415]
2 years ago
8

Jacob bought some supplies for his lemonade stand. He purchased lemons for $4.85, sugar for $3.16, containers for $18. Taxes wer

e included in all the prices. How much money did Jacob spend on all his purchases?
Mathematics
1 answer:
vfiekz [6]2 years ago
7 0

Answer:

26.01

Step-by-step explanation:

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Can segments with lengths of 15, 20, and 36 form a triangle?
strojnjashka [21]
Ok, so remember

the legnth of the longest side must be LESS THAN the sum of the measures of the other 2 sides
if no longest side (becasue it has 2 longest sides or 3 equal sides), then it can form a triangle




so the longest side is 36

36 must be less than the sum  of 15 and 20
36<15+20
36<35
false

therfor it cannot form a triangle
try it yourself, you cannot connect them that way

5 0
3 years ago
C is more than half of n
ycow [4]
Ummm What? soooo what are you looking for? if N is 8 that means C is larger than four. if you want an equation then here you go.

C > N/2
4 0
3 years ago
Read 2 more answers
4(x + 2) represents the area of the rectangle above. Which expression below is equivalent by the Distributive Property?
trasher [3.6K]
We know, distributive property: a(b + c) = ab + ac
4(x + 2) = 4x + 8

In short, Your Answer would be Option B

Hope this helps!
7 0
3 years ago
Read 2 more answers
7.6.35 Question Help A pilot can travel 400 miles with the wind in the same amount of time as 352 miles against the wind. Find t
Law Incorporation [45]

9514 1404 393

Answer:

  21 miles per hour

Step-by-step explanation:

Let w represent the wind speed. Then the travel time is ...

  400/(329 +w) = 352/(329 -w)

  400(329 -w) = 352(329 +w)

  (352+400)w = 329(400 -352)

  w = (400 -352)/(400 +352)·329 = 48/752·329 = 21

The wind speed is 21 miles per hour.

5 0
2 years ago
I need help solving this problem. <img src="https://tex.z-dn.net/?f=4x%20cos%20%5E%7B-1%7D%20%282x%2B4%29-%20%5Csqrt%7B3-3%20x%5
Gnesinka [82]
Given:
f(x)=4xcos^{-1}(2x+4)-\sqrt{3-3x^2}

Using
\frac{d}{dx}cos^{-1}(x)=-\frac{1}{\sqrt{1-x^2}}
we derive
\frac{d}{dx}4xcos^{-1}(2x+4)
=4cos^{-1}(2x+4)-\frac{8x}{\sqrt{1-(2x+4)^2}}

Similarly, using
\frac{d}{dx}\sqrt{x}=\frac{1}{2\sqrt{x}}
we derive
\frac{d}{dx}(-\sqrt{3-3x^2})
=\frac{3x}{\sqrt{3-3x^2}}

Therefore, the derivative is
f'(x)=\frac{d}{dx}(4xcos^{-1}(2x+4)-\sqrt{3-3x^2})
=4cos^{-1}(2x+4)-\frac{8x}{\sqrt{1-(2x+4)^2}}+\frac{3x}{\sqrt{3-3x^2}}
3 0
3 years ago
Read 2 more answers
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