What is the length of the radius in circle C? 3 4 5

Mathematics

1 answer:

Diano4ka-milaya [45]2 years ago

3 0

Answer:

3 but not positive

Step-by-step explanation:

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Using the digits 1 to 9, at most one time each, fill in the boxes so that the points make a parallelogram. Mathematically, use p

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Answer:

$\left\begin{array}{ccc}A\left( \boxed{3} , \boxed{8} \right)&B\left( \boxed{9} , \boxed{6} \right )\\\\C\left( \boxed{1} , \boxed{4} \right)&D\left( \boxed{7} , \boxed{2} \right )\end{array}\right$

Step-by-step explanation:

The coordinates are:

$\left\begin{array}{ccc}A\left( \boxed{3} , \boxed{8} \right)&B\left( \boxed{9} , \boxed{6} \right )\\\\C\left( \boxed{1} , \boxed{4} \right)&D\left( \boxed{7} , \boxed{2} \right )\end{array}\right$

The parallelogram is attached below.

To verify if these coordinates form a parallelogram, we show that:

AB=CD; and
AC=BD

Using Distance Formula

$AB = \sqrt{(6-8)^2+(9-3)^2} = \sqrt{(-2)^2+(6)^2} = \sqrt{40} $ units$

$CD = \sqrt{(2-4)^2+(7-1)^2} = \sqrt{(-2)^2+(6)^2} = \sqrt{40} $ units$

$AC = \sqrt{(8-4)^2+(3-1)^2} = \sqrt{(4)^2+(2)^2} = \sqrt{20} $ units$

$BD = \sqrt{(6-2)^2+(9-7)^2} = \sqrt{(4)^2+(2)^2} = \sqrt{20} $ units$

Since AB=CD; and AC=BD, the coordinates A, B, C, and D form the vertex of a parallelogram.

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Amanda [17]

Answer:

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Answer: A= 110 B=22.5 C=0

Step-by-step explanation:

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