Question

Find the equation of the line parallel to y=6 that contains the point (-1,1). Write the equation in slope intercept form

Answer 1

Given:

The equation of parallel line is $y=6$.

The line contains the point (-1,1).

To find:

The equation of the line.

Solution:

The slope intercept form of a line is:

$y=mx+b$

Where, m is the slope and b is the y-intercept.

The equation of parallel line is

$y=6$

It can be written as

$y=(0)x+6$

The slope of this line is 0.

The slopes of two parallel lines are always equal. So, the slope of the required line is also 0. It passes through the point (-1,1) so the equation of the line is:

$y-y_1=m(x-x_1)$

$y-1=0(x-(-1))$

$y-1=0$

$y=1$

Therefore, the equation of the required line is 1.