The sixth term of an arithmetic sequence is 6
<h3>How to find arithmetic sequence?</h3>
The sum of the first four terms of an arithmetic sequence is 10.
The fifth term is 5.
Therefore,
sum of term = n / 2(2a + (n - 1)d)
where
- a = first term
- d = common difference
- n = number of terms
Therefore,
n = 4
10 = 4 / 2 (2a + 3d)
10 = 2(2a + 3d)
10 = 4a + 6d
4a + 6d = 10
a + 4d = 5
4a + 6d = 10
4a + 16d = 20
10d = 10
d = 1
a + 4(1) = 5
a = 1
Therefore,
6th term = a + 5d
6th term = 1 + 5(1)
6th term = 6
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Answer:
Step-by-step explanation:
y = 2x^2 - 12x +19 Put brackets around the 1st 2 terms. Take 2
y = 2(x^2 - 6x ) + 19 Take 1/2 of the 6 square it and add inside the brackets
y = 2(x^2 - 6 + (6/2)^2) +19 Subtract 2 *9 from the 19. Express 1st 3 terms as ( )^2
y = 2(x- 3)^2 + 19 - 18
y = 2(x - 3)^2 + 1
Answers
y intercept when x = 0 is y = 19
axis of symmetry x = 3
vertex: (3,1)
Graph
graph: red
axis of symmetry: blue
y intercept, vertex: green
Mixed numbers are a mix of a whole number and a fraction
a easy one is
1 and 1/4+1 and 3/4
1 and 1/2 +1 and 1/2
1 and 9/10 and 1 and 1/10
etc
Five times x plus seven equals eighteen
2(b + 3c) → We first need to simplify this.
Simplify.
2b + 6c
1st Option :
3(b + 2c)
Simplify.
3b + 6c
This is INCORRECT, as it is not equal to 2b + 6c.
2nd Option :
(b + 3c) + (b + 3c)
Simplify.
2b + 6c
This is CORRECT because 2b+6c = 2b+6c
(b + 3c) + (b + 3c) → Answer
~Hope I helped!~