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2 years ago

I need help plz plz plz

Mathematics

1 answer:

Katena32 [7]2 years ago

3 0

Your answer to this question is B

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3) Scenario 1 Scenario 2 y = 50x x is time in hours y is distance in miles Compare the scenarios and determine which shows the g

Olegator [25]

Answer:

Option A.

Step-by-step explanation:

Consider the below figure attached with this question.

Scenario 1 represented by the graph.

From the graph it is clear that the line passes through the points (1,60) and (2,120).

Slope of the line is

$y=\dfrac{y_2-y_1}{x_2-x_1}$

$y=\dfrac{120-60}{2-1}=60$

The slope of line is 60. It means the speed is 60 miles per hour.

Scenario 2 defined by the equation,

$y=50x$

If an equation defined as $y=mx+b$ , then m is slope and b is y-intercept.

$m=50$

The slope of line is 50. It means the speed is 50 miles per hour.

The slope of Scenario 1 is greater than slope of Scenario 2. So, the Scenario 1 shows the greater speed.

Hence, the correct option is A.

6 0

2 years ago

Read 2 more answers

Graph the function: <br> f(x)=5/2x-6

MrMuchimi

Plug in any value for x and then you will get y. Use the coordinates to plot.
Example
x= 2
5/2(2)-6
5-6
-1
(2,-1)
Then continue to do the same.

5 0

3 years ago

Select the values that make the inequality g < 2 true.

Semmy [17]

Answer:

-10, -3, -2.001, 1, -7, -2.1, -5, -2.01

Step-by-step explanation:

6 0

3 years ago

Lisa spends part of her year as a member of a gym. She then finds a better deal at another gym, so she cancels her membership wi

Inessa [10]

Step-by-step explanation:

8 0

2 years ago

Write the equation of a circle with center at (3, -2), which also passes through the point (0, 2).

Airida [17]

$\text{The equation of acircle:}\\\\(x-h)^2+(y-k)^2=r^2\\\\(h;\ k)-center\\r-radius\\\\\text{We have center}\ (3,\ -2)\to h=3\ \text{and}\ k=-2.\\\\\text{The radius is the distance between the points} (3,\ -2)\ \text{and}\ (0,\ 2).\\\\\text{The formula of a distance between two points:}\\\\d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}\\\\\text{Substitute:}\\\\d=\sqrt{(2-(-2))^2+(0-3)^2}=\sqrt{4^2+(-3)^2}=\sqrt{16+9}\\\\=\sqrt{25}=5\\\\Answer:\ \boxed{(x-3)^2+(y-(-2))^2=5^2\to\boxed{(x-3)^2+(y+2)^2=25}}$

3 0

3 years ago