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MAXImum [283]
3 years ago
13

Which property justifies that 42 - 37= 42-30+42-7?​

Mathematics
2 answers:
Sladkaya [172]3 years ago
7 0

Answer: distributive property

Step-by-step explanation: This answer may not be right but you never know!

Arada [10]3 years ago
4 0

Answer:

i think it is 54

Step-by-step explanation:

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Find the area of the composite figure.
Roman55 [17]

Answer:

The Area of the composite figure would be 76.26 in^2

Step-by-step explanation:

<u>According to the Figure Given:</u>

Total Horizontal Distance = 14 in

Length = 6 in

<u>To Find :</u>

The Area of the composite figure

<u>Solution:</u>

Firstly we need to find the area of Rectangular part.

So We know that,

\boxed{ \rm \: Area  \:  of \:  Rectangle = Length×Breadth}

Here, Length is 6 in but the breadth is unknown.

To Find out the breadth, we’ll use this formula:

\boxed{\rm \: Breadth = total  \: distance - Radius}

According to the Figure, we can see one side of a rectangle and radius of the circle are common, hence,

\longrightarrow\rm \: Length \:  of \:  the  \: circle = Radius

  • Since Length = 6 in ;

\longrightarrow \rm \: 6 \: in   = radius

Hence Radius is 6 in.

So Substitute the value of Total distance and Radius:

  • Total Horizontal Distance= 14
  • Radius = 6

\longrightarrow\rm \: Breadth = 14-6

\longrightarrow\rm \: Breadth = 8 \: in

Hence, the Breadth is 8 in.

Then, Substitute the values of Length and Breadth in the formula of Rectangle :

  • Length = 6
  • Breadth = 8

\longrightarrow\rm \: Area \:  of  \: Rectangle = 6 \times 8

\longrightarrow \rm \: Area \:  of  \: Rectangle = 48 \: in {}^{2}

Then, We need to find the area of Quarter circle :

We know that,

\boxed{\rm Area_{(Quarter \; Circle) }  = \cfrac{\pi{r} {}^{2} }{4}}

Now Substitute their values:

  • r = radius = 6
  • π = 3.14

\longrightarrow\rm Area_{(Quarter \; Circle) } =  \cfrac{3.14 \times 6 {}^{2} }{4}

Solve it.

\longrightarrow\rm Area_{(Quarter \; Circle) } =  \cfrac{3.14 \times 36}{4}

\longrightarrow\rm Area_{(Quarter \; Circle) } =  \cfrac{3.14 \times \cancel{{36} } \: ^{9} }{ \cancel4}

\longrightarrow\rm Area_{(Quarter \; Circle)} =3.14 \times 9

\longrightarrow\rm Area_{(Quarter \; Circle) } = 28.26 \:  {in}^{2}

Now we can Find out the total Area of composite figure:

We know that,

\boxed{ \rm \: Area_{(Composite Figure)} =Area_{(rectangle)}+ Area_{ (Quarter Circle)}}

So Substitute their values:

  • \rm Area_{(rectangle)} = 48
  • \rm Area_{(Quarter Circle)} = 28.26

\longrightarrow \rm \: Area_{(Composite Figure)} =48 + 28 .26

Solve it.

\longrightarrow \rm \: Area_{(Composite Figure)} =\boxed{\tt 76.26 \:\rm in {}^{2}}

Hence, the area of the composite figure would be 76.26 in² or 76.26 sq. in.

\rule{225pt}{2pt}

I hope this helps!

3 0
2 years ago
Samuel deposited money in an account that pays an annual simple interest rate of 3.5%. at the end of 5 years, samuel earns $2625
evablogger [386]
He has deposited 1500 dollars into the account.
4 0
3 years ago
Read 2 more answers
At a basketball​ game, a team made 54 successful shots. They were a combination of​ 1- and​ 2-point shots. The team scored 93 po
Zepler [3.9K]

Answer:

iwillanswer

Genius

4.3K answers

14.6M people helped

17 one point shots and 39 two point shots were made

Solution:

Given that,

At a basketball​ game, a team made 56 successful shots

They were a combination of​ 1- and​ 2-point shots

Let "x" be the number of 1 point shots

Then, 56 - x is the number of two point shots

The team scored 95 points in all

Therefore,

1(number of 1 point shots) + 2(number of two point shots) = 95

x + 2(56 - x) = 95

x + 112 - 2x = 95

x = 112 - 95

x = 17

Then, number of two point shots = 56 - x = 56 - 17 = 39

Thus 17 one point shots and 39 two point shots were made

8 0
2 years ago
A circle is inscribed with quadrilateral A B C D.
Vlada [557]

Answer:

Its incribed angle theorem

Step-by-step explanation:

I took the test

3 0
3 years ago
Read 2 more answers
CAN SOMEONE HELP ME
Xelga [282]

Answer:

it should be number A hope that helps

7 0
2 years ago
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