<span>1. If my memory serves me well, the answer is true. Free select tool is also called lasso and it’s used to free-hand selection. You can also combine free select tool segments with polygonal segments or other shapes.
2. I think this statement is definitely “False”. As I’ve mentioned before you can combine free selection with other selection features like polygonal by using anchors.
3. I’m not 100% sure, but I guess this one is true. As far as I remember, add to selection mode lets you to add new selection to any existing areas. So I think it’s possible to add selection to the existing one.
4. I think this one is also true. But it allows you just paint it, but it’s also kinda modification. Quick Mask allows you to isolate subject and paint selected object. It helps you not to brush subject accidentally. It’s a very useful tool as for me.
5. Yes, this statement is 100% true. But it could be gray for GIMP, because the mask is coded in gray tones, but I think that black is also gray tone. Color black or gray removes part of selection, and color white adds area to existing selection.
6. According to what I’ve mentioned before this one is also true, so there’s no need for additional explanation.
7. Another tool, similar to the Lasso/Free Select tool is the B) Scissors Tool. As there was mentioned intelligent scissors tool is almost the same as lasso but more user-friendly.
8. It’s false. You must click to the first point of your selection to finish the process or you will lose your selection.
9. I think this one is true. Paths tool includes two or more line segments connected by handle points. These points are kinda anchors I guess.
10. After making a selection using the Paths Tool, I must select the the D) Selection from Path button to turn my path into a selection. You can find it in path tool options.
11. Yes, it’s true, it allows you to make complex selections with curved or straight lines. Just drag one of the anchors to curve the line. Also you can create different geometrical figures with this tool.
12. Yes this is true. But there are much more cool blur filters than only Gaussian blur. Experiment on your own.
13. You can do all of the following given above. Every layer is kinda isolated image and you can modify it however you want.
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14. I’m definitely sure that this statement is true. Just find layer drop down menu and follow the instructions given in this question. It’s simple.</span></span>
Answer:
Write out your birthday in the following format: M/DD/YY. For example, if your birthday is on June 11, 2013, it would be written as 6/11/13.
2. Convert the birthday date to binary format. Using our same example from above, 6/11/13 translated into binary code would be: 110/1011/1101.
3. Select one color of bead to represent “0”, a second color to represent “1” and then the third color to represent a space (/) between the numbers.
4. Layout the beads to represent your birthdate in binary code. Don’t forget the third color for the spaces in between the numbers!
5. Once laid out, string all the beads on to the string or pipe cleaner.
6. Tie a knot around the ends and enjoy your one-of-a kind masterpiece as a piece of jewelry or a bag tag….the options are endless!
Answer:
- import math
-
- def standard_deviation(aList):
- sum = 0
- for x in aList:
- sum += x
-
- mean = sum / float(len(aList))
-
- sumDe = 0
-
- for x in aList:
- sumDe += (x - mean) * (x - mean)
-
- variance = sumDe / float(len(aList))
- SD = math.sqrt(variance)
-
- return SD
-
- print(standard_deviation([3,6, 7, 9, 12, 17]))
Explanation:
The solution code is written in Python 3.
Firstly, we need to import math module (Line 1).
Next, create a function standard_deviation that takes one input parameter, which is a list (Line 3). In the function, calculate the mean for the value in the input list (Line 4-8). Next, use the mean to calculate the variance (Line 10-15). Next, use sqrt method from math module to get the square root of variance and this will result in standard deviation (Line 16). At last, return the standard deviation (Line 18).
We can test the function using a sample list (Line 20) and we shall get 4.509249752822894
If we pass an empty list, a ZeroDivisionError exception will be raised.
Answer:
Comparison.
Explanation:
When we have to find a largest in a list of n elements.First we have to iterate over the list so we can access all the elements of the list in one go.Then to find the largest element in the list we have to initialize a variable outside the loop with the minimum value possible and in the loop compare each element with this value,if the element is greater than the variable assign the element to the variable.Then the loop will find the largest element and it will be the variable.