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Marat540 [252]
2 years ago
10

A freight train departs from one train station to its destination at a constant speed. Suppose the distance the train is from th

e station in miles is represented as a function of the number of hours after the train departed from the train station. If the graph of the function passes through the points (0.5, 135) and (2,81), what is the distance between the train station and the freight train's destination? (1 point) A. 189 miles B. 171 miles C. 153 miles D. 162 miles​
Mathematics
1 answer:
barxatty [35]2 years ago
6 0

Answer:

108 miles

Step-by-step explanation:

Given the points (0.5, 135) and (2,81)

Diatnce between two points :

D = √(x2 - x1)² + (y2 - y1)²

X1 = 0.5 ; y1 = 135 ; x2 = 2 ; y2 = 81

D = √(2^2 - 0.5^2) + (81^2 - 135^2)

D = √(4 - 0.25) + (6561 - 18225)

D = √3.75 −11664

D = 107.98263

D = 108 miles

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Kate hiked 14 miles in 6 hours. Which rate represents the number of miles traveled per hour? L
12345 [234]

Answer:

That would be 14 miles ÷ 6 hours which would be 2.3333 or 2 and 1/3

6 0
2 years ago
-k+0.03+1.01k=-2.45-1.81k?
Mrrafil [7]

Answer:

-1.362637

or if you round your answer -1.36

Step-by-step explanation:

solve for k by simplifying both sides of the equation and isolating the variable.

4 0
3 years ago
What is the range of possible sizes for side x?
faust18 [17]
0.5 < x < 16.5 given: Two sides of triangle: 8.0 units and 8.5 units
Measure of third side = x
According to the triangle's inequality,
Sum of any two sides > third side. (i)
Difference between the sides < third side. (ii)
If x is the third side, then
x < 8+8.5 [Using (i)]
i.e. x< 16.5
Also, x > 8.5-8 [Using (ii)]
i.e. x> 0.5
Hence, Range of possible sizes for side x would be 0.5 < x < 16.5.
6 0
2 years ago
Read 2 more answers
What is the difference? startfraction 2 x 5 over x squared minus 3 x endfraction minus startfraction 3 x 5 over x cubed minus 9
weeeeeb [17]

The difference of the expression \frac{2x^5}{x^2 - 3x} - \frac{3x^5}{x^3 - 9x} is \frac{2x^5(x + 3) - 3x^5}{x(x - 3)(x + 3)}

<h3>How to determine the difference?</h3>

The expression is given as:

\frac{2x^5}{x^2 - 3x} - \frac{3x^5}{x^3 - 9x}

Factor the denominators of the expressions:

\frac{2x^5}{x(x - 3)} - \frac{3x^5}{x(x^2 - 9)}

Apply the difference of two squares to x² - 9

\frac{2x^5}{x(x - 3)} - \frac{3x^5}{x(x - 3)(x + 3)}

Take LCM

\frac{2x^5(x + 3) - 3x^5}{x(x - 3)(x + 3)}

Hence, the difference of the expression \frac{2x^5}{x^2 - 3x} - \frac{3x^5}{x^3 - 9x} is \frac{2x^5(x + 3) - 3x^5}{x(x - 3)(x + 3)}

Read more about expressions at:

brainly.com/question/723406

#SPJ4

6 0
2 years ago
The area of triangle ABC is 24 square centimeters. If B = 30° and a = 6 cm, what is the measure of side c? 4 cm 8 cm 16 cm 32 cm
disa [49]

Answer:

16 cm

Step-by-step explanation:

Given : The area of triangle ABC is 24 square centimeters.

To Find: If B = 30° and a = 6 cm, what is the measure of side c?

Solution:

Formula : Area = \frac{1}{2} \times a \times c \times sin B

a = 6

Area = 24

B = 30°

Substitute the values in the formula

24 = \frac{1}{2} \times 6 \times c \times sin 30

24 = \frac{1}{2} \times 6 \times c \times \frac{1}{2}

24 =3 \times c \times \frac{1}{2}

\frac{24 \times 2}{3} =c

16=c

Hence the measure of side c is 16 cm

So, Option c is correct.

4 0
3 years ago
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