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3 years ago

Assemble the proof by dragging tiles to the statements and reasons columns.

Mathematics

2 answers:

WINSTONCH [101]3 years ago

7 0

Answer:

QR parallel PT, given

<QPR=<STR, given

<QRP & <SRT are all right angles, def of perpendicular

<QRP = <SRT, all right angles are =

PQR~TSR, AA similarity theorem

Step-by-step explanation:

weeeeeb [17]3 years ago

3 0

Answer:

Step-by-step explanation:

Given;

Δ QPR ≅ ∠ STR

i) $\frac{QP}{ST} = \frac{QR}{SR} = \frac{PR}{TR}$

ii )∠ PRQ = ∠ TRS ( Both are 90° since QR ⊥ PT )

iii) ∠ RPQ = ∠ STR ( same side ratio from (i) )

Hence it is proved that

Δ PQR $\sim$ Δ TSR

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