Question

Assemble the proof by dragging tiles to the statements and reasons columns.

Answer 1

Answer:

QR parallel PT, given

<QPR=<STR, given

<QRP & <SRT are all right angles, def of perpendicular

<QRP = <SRT, all right angles are =

PQR~TSR, AA similarity theorem

Step-by-step explanation:

Answer 2

Answer:

Step-by-step explanation:

Given;

Δ QPR ≅ ∠ STR

 i)  $\frac{QP}{ST} = \frac{QR}{SR} = \frac{PR}{TR}$

ii )∠ PRQ = ∠ TRS     ( Both are 90° since QR ⊥ PT )

iii) ∠ RPQ = ∠ STR     ( same side ratio from (i) )

Hence it is proved that

Δ PQR $\sim$ Δ TSR