All categories

3 years ago

SOMEONE HELP PLZZZ ASAP

Mathematics

2 answers:

ivolga24 [154]3 years ago

6 0

Answer:

Answer:

(2x−1)(2x−1)(2x−1)(2x−1)

Step-by-step explanation:

Factor 16x4−32x3+24x2−8x+1

16x4−32x3+24x2−8x+1

=(2x−1)(2x−1)(2x−1)(2x−1)

egoroff_w [7]3 years ago

4 0

This means you replace every x in h(x) with f(x).
So it would be (2x-1)^4
Which is equivalent to (2x-1) (2x-1) (2x-1) (2x-1)
Whenever you do foil and simplify, you get -

16x^4 - 32x^3 + 24x^2 - 8x + 1

(Could I have my first brainliest?)

You might be interested in

What two numbers multiply to get 120 and add or subtract to get negative 22?

Lesechka [4]

The two numbers are -10 and -12
Bcause -10 × -12 = +120
And when subtracted-10 -12 = -22

7 0

3 years ago

Read 2 more answers

Which equation is graphed here?

Zolol [24]

Answer:

y-4= -3/2(x+2)

Step-by-step explanation:

⋆✨ANSWERED BY KAKASHI ʕ•㉨•ʔ✨⋆

✨BRAINLIEST WILL BE APPRECIATED✨

✨IF YOU HAVE ANY OTHER QUESTIONS ASK IN THE COMMENT BOX✨

8 0

3 years ago

Read 2 more answers

Sophie Ruth is eating a

Firdavs [7]

Answer:

15 grams

Step-by-step explanation:

There is a 50 gram chocolate bar that contains 30% cocoa. So we are basically finding 30% of 50. We break 30 into 3*10 and 50 into 5*10. 5*3 = 15.

Therefore, there are 15 grams of cocoa in the chocolate bar.

I hope this helps.

6 0

3 years ago

Find the unit rate kenny reads 5/8 pages in 2/3 minutes

Cerrena [4.2K]

.9375 pages / 1 minute

or 15/16 pages for every 16/16 minute.

4 0

3 years ago

In a study of the accuracy of fast food drive-through orders, McDonald’s had 33 orders that were not accurate among 362 orders o

melomori [17]

Answer:

A. We need to conduct a hypothesis in order to test the claim that the true proportion of inaccurate orders p is 0.1.

B. Null hypothesis: $p=0.1$

Alternative hypothesis: $p \neq 0.1$

C. $z=\frac{0.0912 -0.1}{\sqrt{\frac{0.1(1-0.1)}{362}}}=-0.558$

D. $z_{\alpha/2}=-1.96$ $z_{1-\alpha/2}=1.96$

E. Fail to the reject the null hypothesis

F. So the p value obtained was a very high value and using the significance level given $\alpha=0.05$ we have $p_v>\alpha$ so we can conclude that we have enough evidence to FAIL to reject the null hypothesis, and we can said that at 5% of significance the true proportion of inaccurate orders is not significantly different from 0.1.

Step-by-step explanation:

Data given and notation

n=362 represent the random sample taken

X=33 represent the number of orders not accurate

$\hat p=\frac{33}{363}=0.0912$ estimated proportion of orders not accurate

$p_o=0.10$ is the value that we want to test

$\alpha=0.05$ represent the significance level

Confidence=95% or 0.95

z would represent the statistic (variable of interest)

$p_v$ represent the p value (variable of interest)

A: Write the claim as a mathematical statement involving the population proportion p

We need to conduct a hypothesis in order to test the claim that the true proportion of inaccurate orders p is 0.1.

B: State the null (H0) and alternative (H1) hypotheses

Null hypothesis: $p=0.1$

Alternative hypothesis: $p \neq 0.1$

When we conduct a proportion test we need to use the z statistic, and the is given by:

$z=\frac{\hat p -p_o}{\sqrt{\frac{p_o (1-p_o)}{n}}}$ (1)

The One-Sample Proportion Test is used to assess whether a population proportion $\hat p$ is significantly different from a hypothesized value $p_o$ .

C: Find the test statistic

Since we have all the info required we can replace in formula (1) like this:

$z=\frac{0.0912 -0.1}{\sqrt{\frac{0.1(1-0.1)}{362}}}=-0.558$

D: Find the critical value(s)

Since is a bilateral test we have two critical values. We need to look on the normal standard distribution a quantile that accumulates 0.025 of the area on each tail. And for this case we have:

$z_{\alpha/2}=-1.96$ $z_{1-\alpha/2}=1.96$

P value

It's important to refresh the p value method or p value approach . "This method is about determining "likely" or "unlikely" by determining the probability assuming the null hypothesis were true of observing a more extreme test statistic in the direction of the alternative hypothesis than the one observed". Or in other words is just a method to have an statistical decision to fail to reject or reject the null hypothesis.

The significance level provided $\alpha=0.05$ . The next step would be calculate the p value for this test.

Since is a bilateral test the p value would be:

$p_v =2*P(z$

E: Would you Reject or Fail to Reject the null (H0) hypothesis.

Fail to the reject the null hypothesis

F: Write the conclusion of the test.

So the p value obtained was a very high value and using the significance level given $\alpha=0.05$ we have $p_v>\alpha$ so we can conclude that we have enough evidence to FAIL to reject the null hypothesis, and we can said that at 5% of significance the true proportion of inaccurate orders is not significantly different from 0.1.

6 0

3 years ago