Answer:
A(lawn) = 68 m²
Step-by-step explanation:
A(lawn) = Agarden - Aflower - Avegetables
= 10m×14m - 3m×8m/2 - (5m+7m)×10m/2
= 140m² - 12m² - 60m²
= 68 m²
A(rectangle) = w × h
A(triangle) = ½ × b × h
A(trapeze) = ½(B+b) × h
Answer:
The procedure emphasizes the idea of the summation of one physical quantity. In this case, X.
Step-by-step explanation:
1. When we add fractions like these we do it simply by rewriting a new one, the summation of the numerators over the same denominator:

The procedure emphasizes the idea of the summation of one physical quantity, in this case, X.
2) This physical quantity x could be miles, oranges, gallons, etc.
Step-by-step explanation:
let father's age be f yr old and son age be s yr old
f = 5s -(1)
f + s = 60 -(2)
sub (1) into (2):
5s + s = 60
6s = 60
s = 10
f = 60 - 10 = 50
in 5 yr time, father age = 50 + 5 = 55
son age = 10 + 5 = 15
Answer:
H0: u1 - u2 = 0
H1: u1 - u2 ≠ 0
Step-by-step explanation:
This question requires us to state the hypothesis to be used for this test to know if males and females have the same amount of substance X. I have gone further to also calculate the test statistics too.
Null hypothesis:
H0: u1 - u2 = 0
Alternative hypothesis:
H1: u1 - u2 ≠ 0
X1 = 28, sd1 = 14.1, n1 = 75
X2 = 33, sd2 = 9.5, n2 = 50
We have a 2 tailed test
Alpha = 1-0.8812
= 0.1188
Critical value = 1.56
If z<-1.56 or z>1.56
Reject null hypothesis
Test statistic
= (28-33)/14.1²/75 + 9.5²/50
= -2.37
Therefore we reject the H0 because -2.37 is less than -1.56