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LiRa [457]
3 years ago
7

HELP PLEASEEE !!! 50 POINTS

Mathematics
2 answers:
Archy [21]3 years ago
8 0

Answer:

Step-by-step explanation For the first on 5 and -4 all u do is divide y over x so it wpuld be -4/5 which would be -0.8

just keep doing the process of dividing y over x

the second 1 would be 0/3 which is 0

just keep doing this process

ipn [44]3 years ago
4 0

Answer:

haha

Step-by-step explanation:

first off thats not 50 points

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A rectangle has perimeter 28cm. Its area is 42sq.cm. Determine the dimensions of the rectangle. Include a diagram in your soluti
yawa3891 [41]

The dimensions of the rectangle are: b=9.65 cm and h=4.35 cm or b=4.35 cm and h= 9.65 cm.

<h3>Quadrilaterals</h3>

There are different types of quadrilaterals, for example, square, rectangle, rhombus, trapezoid, and parallelogram.  Each type is defined accordingly to its length of sides and angles. For example, in a rectangle,  the opposite sides are equal and parallel and their interior angles are equal to 90°.

The area of a rectangle is equal to base x height (A=bh). The perimeter of a geometric figure is the sum of its sides. Thus, for a rectangle, the perimeter is 2b+2h.

<h3>System of Linear Equations</h3>

System of linear equations is the given term math for two or more equations with the same variables. The solution of these equations represents the point at which the lines intersect.

The question gives:

Perimeter=28cm

Area= 42 cm²

If the perimeter is the sum of all sides of the rectangle, you have:

Perimeter= 2b+2h=28

If the area of the rectangle is 42cm², you have:

Area=bh=42 cm²

You can write a system of linear equations.

2b+2h=28 (1)

bh=42 (2)

From equation 2, you have  b=\frac{42}{h}. Then, you can replace it in equation 1.

2*\frac{42}{h}+2h=28 \\ \\ 84+2h^2=28h\\ \\ 2h^2-28h+84=0 \; dividing\; by\; 2\\ \\ h^2-14h+42=0

Now, you should solve the quadratic equation.

h_{1,\:2}=\frac{-\left(-14\right)\pm \sqrt{\left(-14\right)^2-4\cdot \:1\cdot \:42}}{2\cdot \:1}

h_{1,\:2}=\frac{-\left(-14\right)\pm \:2\sqrt{7}}{2\cdot \:1}

h_1=\frac{-\left(-14\right)+2\sqrt{7}}{2\cdot \:1}=7+\sqrt{7}=9.65 cm

h_2=\frac{-\left(-14\right)-2\sqrt{7}}{2\cdot \:1}=7-\sqrt{7}=4.35cm

If h1=9.65 cm, then b_1=\frac{42}{9.65} =4.35 cm, and if  h2=4.35 cm, then b_1=\frac{42}{4.35} =9.65 cm.

Read more about the quadratic function here:

brainly.com/question/1497716

#SPJ1

8 0
1 year ago
HELP ME PLEASEEEE I BEG YOUUU
Alex777 [14]

Answer:

1.a. E>D

b. E<F

2. Yes. There are multiple combinations on how to do number 1. The first question asks how for a, you need a letter that is bigger than another letter, and for b, you need a letter that is smaller than the other letter's value. There are many ways to go about that previous problem.

Step-by-step explanation:

Hello!

To solve this question, we first need to realize that this is a simple number line. A number line is just a line that contains multiple points from the left being negative, middle is zero, and right becoming increasingly positive.

In this case, D is zero, and A-C are deemed negative. E-F are positive.

For a, we need to find a point that is bigger than another point.

We have various answers for this. F is bigger than A-E, E is bigger than A-D, D is bigger than A-C, C is bigger than A-B, and B is bigger than A. As long as any of your answer goes along this format it is correct.

B is asking a number that is smaller than that said number. A is smaller to B-F, B is smaller to C-F, C is smaller to D-F, E is smaller to F. So again, any letter combination that falls within this category is correct.

For the last one, there are multiple combinations, meaning there is just not one answer that fulfills that question.

6 0
2 years ago
Y-3=4(X+2) in slope intecept form
ELEN [110]
Y - 3 = 4x + 8
y = 4x + 11

slope = 4
3 0
3 years ago
Find the distance between (4,-2) &amp; (-1,3)
AleksAgata [21]

Step-by-step explanation:

Use Pythagorean theorem here. To find the height, find the difference of the 2 y's. To find the length, find the difference between the 2 x's.

Length = x2 - x1

Height = y2 - y1

√length^2 + height^2 = distance

√5^2 + 5^2 = √50 = 7.07

8 0
3 years ago
What is the distance around this rectangle 12 4/5 inches 2 1/8 inches
wlad13 [49]
I think the answer is 14 6/3
3 0
3 years ago
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