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Morgarella [4.7K]
3 years ago
11

There are 3 bracelets with 6 beads how many beads are there together whats 3 times 6

Mathematics
1 answer:
Studentka2010 [4]3 years ago
3 0

Answer:

18

Step-by-step explanation:

6 x 3 = 18

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Helppppppppp pleaseeeeeee
choli [55]

Answer:

Going from up to down

Box #1=0

Box #2=3

Box #3=5

Step-by-step explanation:

8 0
4 years ago
Read 2 more answers
One positive number exceeds another by 2, and their product is 80. Find the numbers​
katen-ka-za [31]

Answer:

The Answer is: The first number is 10 and the second number is 8.

Step-by-step explanation:

Let f = first number and s = second number.

The first number is 2 larger than the second:

f = n + 2

The numbers times each other is 80:

f * n = 80

Substitute the value of f, which is (n + 2):

n(n + 2) = 80

n^2 + 2n = 80

n^2 + 2n - 80 = 0

(n + 10)(n - 8) = 0

n^2 + 10n - 8n - 80 = 0, so the first number is 10 and the second one is 8.

Another method, just from thinking about it:

factor 80:

8 * 10, is the first factoring I thought of. I then noted that the difference between the two is 2 and if you multiply them they equal 80.

Hope this helps! Have an Awesome Day!! :-)

6 0
3 years ago
Each item produced by a certain manufacturer is independently of acceptable quality with probability 0.95. Approximate the proba
Diano4ka-milaya [45]

Answer:

The probability that at most 10 of the next 150 items produced are unacceptable is 0.8315.

Step-by-step explanation:

Let <em>X</em> = number of items with unacceptable quality.

The probability of an item being unacceptable is, P (X) = <em>p</em> = 0.05.

The sample of items selected is of size, <em>n</em> = 150.

The random variable <em>X</em> follows a Binomial distribution with parameters <em>n</em> = 150 and <em>p</em> = 0.05.

According to the Central limit theorem, if a sample of large size (<em>n</em> > 30) is selected from an unknown population then the sampling distribution of sample mean can be approximated by the Normal distribution.

The mean of this sampling distribution is: \mu_{\hat p}= p=0.05

The standard deviation of this sampling distribution is: \sigma_{\hat p}=\sqrt{\frac{ p(1-p)}{n}}=\sqrt{\frac{0.05(1-.0.05)}{150} }=0.0178

If 10 of the 150 items produced are unacceptable then the probability of this event is:

\hat p=\frac{10}{150}=0.067

Compute the value of P(\hat p\leq 0.067) as follows:

P(\hat p\leq 0.067)=P(\frac{\hat p-\mu_{p}}{\sigma_{p}} \leq\frac{0.067-0.05}{0.0178})=P(Z\leq 0.96)=0.8315

*Use a <em>z</em>-table for the probability.

Thus, the probability that at most 10 of the next 150 items produced are unacceptable is 0.8315.

5 0
3 years ago
What error did Tracy make? She used AG = 2EG, but the correct statement is 2AG = GE. She found that x = 4, but the correct value
azamat

Answer:

C. She used GF = 2BG, but the correct statement is BG = 2GF.

Step-by-step explanation:

credits to the other person!

8 0
3 years ago
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Jayne is making a patchwork quilt. She is following a pattern for a triangular section but only knows the measurements shown. Wh
Novosadov [1.4K]

Answer:

20.0

Step-by-step explanation:

4 0
3 years ago
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