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erastova [34]
2 years ago
14

What is the answer to this? Plz answer! It's due tomorrow!!!!!​

Mathematics
1 answer:
Leya [2.2K]2 years ago
4 0

Answer: the third answer (C)

Step-by-step explanation:

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Please help me answer all parts of the question in the photo.
goldenfox [79]
z_1=4+2i\\z_2=-1+2i\\\overline(z_2)=\sqrt{(-1)^2+(2i)^2}=\sqrt{1-4}=i\sqrt{3}\\ z_1+\overline(z_1)=4+2i+\sqrt{4^2+(2i)^2}=4+2i+\sqrt{16-4}=4+\sqrt{12}+2i\\z_2+\overline(z_2)=-1+2i+\sqrt{(-1)^2+(2i)^2}=-1+2i+\sqrt{1-4}=-1+(2+\sqrt{3})i
3 0
3 years ago
-(19-2a^2)-57+4g^2 simplify, and please include step by steps thanks
Katyanochek1 [597]

Answer:

2(-17+a^2+2g^2)

Step-by-step explanation:

step1

3 0
3 years ago
There are 3 people pulling on an object, the first person pulls with a force of 226 newtons at a direction of 145 degrees the se
Alona [7]

Answer:

R=883.74N

Step-by-step explanation:

From the question we are told that:

Force 1 F_1=226N

Force 2 F_2=331N

Force 3 F_3=377N

Direction 1  \theta_1=145 degrees \approx 35 \textdegree (2nd qudrant)

Direction 2 \theta_2=303 degrees \approx 57 \textdegree (3rd qudrant)

Direction 3 \theta_3=77 degrees

Generally Resolving forces to X axis is mathematically given by

 \sum f_x=337cos77+331cos57+226sin35

 \sum f_x=351.596N

Generally Resolving forces to Y axis is mathematically given by

 \sum f_y=337sin77+331sin57+226cos35

 \sum f_x=810.788N

Generally the equation for Resultant force R is mathematically given by

 R=\sqrt{\sum f_x^2+\sum f_x^2}

 R=\sqrt{351.596^2+810.788^2}

 R=883.74N

7 0
2 years ago
1/2 Of the class has blonde hair and 1/4 the class has black hair.1/4 of the class has brown hair If there are 32 kids in the cl
Mariulka [41]

Answer:

Step-by-step explanation:

so there is 32 kids....1/2 are blonde, 1/4 have black hair, 1/4 have brown hair

1/2(32) = 32/2 = 16 are blonde

1/4(32) = 32/4 = 8 have black hair

1/4(32) = 32/4 = 8 have brown hair

6 0
2 years ago
The coordinates of the vertices of ΔPQR are (–2, –2), (–6, –2), and (–6, –5).
melamori03 [73]
<h3>Answer:</h3>

Yes, ΔPʹQʹRʹ is a reflection of ΔPQR over the x-axis

<h3>Explanation:</h3>

The problem statement tells you the transformation is ...

... (x, y) → (x, -y)

Consider the two points (0, 1) and (0, -1). These points are chosen for your consideration because their y-coordinates have opposite signs—just like the points of the transformation above. They are equidistant from the x-axis, one above, and one below. Each is a <em>reflection</em> of the other across the x-axis.

Along with translation and rotation, <em>reflection</em> is a transformation that <em>does not change any distance or angle measures</em>. (That is why these transformations are all called "rigid" transformations: the size and shape of the transformed object do not change.)

An object that has the same length and angle measures before and after transformation <em>is congruent</em> to its transformed self.

So, ... ∆P'Q'R' is a reflection of ∆PQR over the x-axis, and is congruent to ∆PQR.

6 0
3 years ago
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