Question

A store buys a camera for $80 and decides to markup the price 35%. How much does the camera sell for?

Answer 1

Answer:

The camera is sold for $ 59.26.

Step-by-step explanation:

From the statement we understand that the new price of the camera ($C'$) is calculated by:

$C' = \frac{C_{o}}{\left(1+\frac{r}{100} \right)}$ (1)

Where:

$C'$ - Price after increase, measured in US dollars.

$r$ - Increase rate, expressed in percentage.

If we know that $C_{o} = 80\,USD$ and $r = 35$, then the new price of the camera is:

$C' = \frac{80\,USD}{1+\frac{35}{100} }$

$C' = 59.26\,USD$

The camera is sold for $ 59.26.