Answer:
x = - 8 and (- 8, 0 )
Step-by-step explanation:
Given a quadratic in standard form
y = ax² + bx + c ( a ≠ 0 )
Then the equation of the axis of symmetry which is also the x- coordinate of the vertex is
x = - 
y = x² + 16x + 64 ← is in standard form, with
a = 1 and b = 16, then
x = -
= - 8
Equation of axis of symmetry is x = - 8
Substitute x = - 8 into the quadratic and evaluate for y
y = (- 8)² + 16(- 8) + 64 = 64 - 128 + 64 = 0
vertex = (- 8, 0 )
Answer:
The length of he hypotenuse of the triangle is x = 65.
Step-by-step explanation:
Here, the base of the right triangle = 56
The perpendicular = 33
The hypotenuse of the triangle = x
Now, by PYTHAGORAS THEOREM: In a right angled triangle

or, here

or, 
Hence, the length of he hypotenuse of the triangle is 65.
<span>I'm guessing you are saying...
6, 12, 18, 24, 30, 36, 42, 48, 54, 60,
66, 72, 78, 84, 90, 96, 102, 108, 114, 120,
126, 132, 138, 144, 150, 156, 162, 168, 174, 180,
186, 192, 198, 204, 210, 216, 222, 228, 234, 240,
246, 252, 258, 264, 270, 276, 282, 288, 294, 300,
306, 312, 318, 324, 330, 336, 342, 348, 354, 360,
366, 372, 378, 384, 390, 396, 402, 408, 414, 420,
426, 432, 438, 444, 450, 456, 462, 468, 474, 480,
486, 492, 498, 504, 510, 516, 522, 528, 534, 540,
546, 552, 558, 564, 570, 576, 582, 588, 594, 600
Hope this helps ;)</span>