F1 . . . 100% of it = 900N is in the +x direction.
F2 . . . 70.7% of it (cos45°, 530.3N) is in the +x direction,
and 70.7% of it (sin45°, 530.3N) is in the +y direction.
F3 . . . 80% of it (520N) is in the -x direction,
and 60% of it (390N) is in the +y direction.
Total x-component: 900 + 530.3 - 520 = 1,950.3 N
Total y-component: 530.3 + 390 = 920.3 N
Magnitude of the resultant = √ (x² + y²)
= √(1950.3² + 920.3²)
= √4,650,070.09
= 2,156.4 N .
Angle of the resultant, measured counterclockwise
from the +x axis, is
tan⁻¹ (y / x)
= tan⁻¹ (920.3 / 1950.3)
= tan⁻¹ (0.4719)
= about 25.3° .
Caution:
The same fatigue that degrades my ability to READ the question accurately
may also compromise the accuracy of my solutions. Before you use this
answer for anything, check it, check it, check it !
12.96 can be rounded to 13 if you're rounding to the nearest tenth and ones digit. If it is the tens digit, 12.96 can be rounded to 10.
A,81 because if you try checking 81 will be the only composite number im in 6 grade.....
Answer:
Depth = 3.3 inches
Step-by-step explanation:
Given that the shape of the satellite looks like a parabola
The equation of parabola is given as follows
Where
a= 13
Therefore
Lets take (13 , y) is a
Now by putting the values in the above equation we get
y=3.25 in
Therefore the depth of the satellite at the nearest integer will be 3.3 inches.
Depth = 3.3 inches
