I'm assuming a 5-card hand being dealt from a standard 52-card deck, and that there are no wild cards.
A full house is made up of a 3-of-a-kind and a 2-pair, both of different values since a 5-of-a-kind is impossible without wild cards.
Suppose we fix both card values, say aces and 2s. We get a full house if we are dealt 2 aces and 3 2s, or 3 aces and 2 2s.
The number of ways of drawing 2 aces and 3 2s is
and the number of ways of drawing 3 aces and 2 2s is the same,
so that for any two card values involved, there are 2*24 = 48 ways of getting a full house.
Now, count how many ways there are of doing this for any two choices of card value. Of 13 possible values, we are picking 2, so the total number of ways of getting a full house for any 2 values is
The total number of hands that can be drawn is
Then the probability of getting a full house is
Answer:
I have no idea how to answer this... :P
<3
Sorry, I am quite a dummy.
The mean would shift to the left because, simply, the average price of the car would go DOWN.
Point slope from would be 12x-y+26=0.
Black is the equation, 12x-y+26=0.
- Orange is <em>y-14=12(x+1)</em>
- Blue is <em>y-14=12(x-1)</em>
- Red is <em>y+14=12(x-1)</em>
- Green is <em>y-14=-12(x+1)</em>
The area of the rectangle is 
units.
Step-by-step explanation:
Step 1:
The area of a rectangle is obtained by multiplying the length with the width of the rectangle.
Considering this a whole rectangle, the length of the rectangle is 5 units and the width is the sum of 
, 
, and -6.
So the length of the rectangle = 5 units and
the width of the rectangle 
units.
The area of a rectangle = (length)(width).
Step 2:
By substituting the known values, we get
The area of the rectangle 
So the area of the rectangle is units.
