For the answer to the question above,
<span>a) Use F = k * q1 * q2 / d²
where k = 8.99e9 N·m²/C²
and q1 = -1.602e-19 C (electron)
and q2 = 1.602e-19 C (proton)
and d = distance between point charges = 0.53e-10 m
The negative result indicates "attraction".
b) Here, just use F = ma
where F was found above, and
m = mass of electron = 9.11e-31kg, if memory serves
a = radial acceleration
c) Now use a = v² / r
where a was found above
and r was given
d) period T = 2π / ω = 2πr / v
where v was found above
and r was given </span>
Answer:
x= -15/2 y=-33/2
Step-by-step explanation:
i dont know how you want to solve it but if it is "system of equations" then first solve for the first variable in on e of the equations, then substitute the result into the other equation.
Comment
You have to begin by declaring what g(f(x)) means. It means that wherever you see an x in g(x) you put in f(x).
It will look like this to start with
g(f(x)) = (f(x) + 5) / (f(x)
Now substitute into this for g(-3)
g(x^2 + 5) = (x^2 + 5 + 5)/(x^2 + 5) It's time to use some numbers.
g(- 3) = ((-3)^2 + 10)/( (-3)^2 +5)
g(-3) = ( 9 + 10 ) / ( 9 + 5)
g(-3) = (19)/14 <<<<<< answer.
C <<<< answer.
<span>5° below zero is -5 degrees
</span><span>The temperature of a solution in beaker two what is the opposite of the temperature in beaker one so it's 5 degrees above zero
</span>
answer
<span>5° above zero</span>
Answer:
c
Step-by-step explanation:
12.50*6=75
45.25*3=135.75
135.75+75=210.75
