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Len [333]
3 years ago
6

What is 15 out of 24 as a percent?

Mathematics
1 answer:
vitfil [10]3 years ago
3 0
It is 62.5 you will divide 15 out of 24 then multiply by 100
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How to solve this question
Viefleur [7K]

Answer:

7x+21 = 7x + 21

Step-by-step explanation:

7(x+3)=6-(-7x - 15)

L.H.S

=7(x+3)

=7x+21 (multiply 7 by (x+3))

R.H.S:

=6-(-7x - 15)

= 6+7x+15 (multiply the -ive sign in the bracket)

= 7x + 21 ( adding 15 and 6)

now compare the two sides

7x+21 = 7x + 21 hence we prove that L.H.S= R.H.S

4 0
3 years ago
The projected rate of increase in enrollment at a new branch of the UT-system is estimated by E ′ (t) = 12000(t + 9)−3/2 where E
nexus9112 [7]

Answer:

The projected enrollment is \lim_{t \to \infty} E(t)=10,000

Step-by-step explanation:

Consider the provided projected rate.

E'(t) = 12000(t + 9)^{\frac{-3}{2}}

Integrate the above function.

E(t) =\int 12000(t + 9)^{\frac{-3}{2}}dt

E(t) =-\frac{24000}{\left(t+9\right)^{\frac{1}{2}}}+c

The initial enrollment is 2000, that means at t=0 the value of E(t)=2000.

2000=-\frac{24000}{\left(0+9\right)^{\frac{1}{2}}}+c

2000=-\frac{24000}{3}+c

2000=-8000+c

c=10,000

Therefore, E(t) =-\frac{24000}{\left(t+9\right)^{\frac{1}{2}}}+10,000

Now we need to find \lim_{t \to \infty} E(t)

\lim_{t \to \infty} E(t)=-\frac{24000}{\left(t+9\right)^{\frac{1}{2}}}+10,000

\lim_{t \to \infty} E(t)=10,000

Hence, the projected enrollment is \lim_{t \to \infty} E(t)=10,000

8 0
2 years ago
-3z-z answer please fast​
ch4aika [34]

Answer:

-4z

Step-by-step explanation:

4 0
3 years ago
BAD is congruent to BCD by <br> the
scoundrel [369]
AB is congruent to BC
6 0
3 years ago
AB ← → is tangent to circle O at point A. If m∠AOB = 55°, what is m∠ABO ?
AlladinOne [14]
A tangent forms a right angle with the centre of circle at the point it touches the circumference. i.e. OAB = 90 degrees
If AOB = 55 degrees, then ABO = 90 - 55 = 35 degrees
3 0
3 years ago
Read 2 more answers
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