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bazaltina [42]
2 years ago
6

2x+1 divided by 8x^3+18x^2+11x+2

Mathematics
1 answer:
yuradex [85]2 years ago
8 0

Answer:

1/4x^2+7x+2

Step-by-step explanation:

hope this helps

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What is 10 + x = 23?
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Answer:

x = 13

Step-by-step explanation:

This is a simple algebraic problem. Since x must be left by itself in order to solve, we subtract 10 on both sides, giving us the final answer of x = 13.

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Step-by-step explanation:

Follow PEMDAS

2 ∙ (8 + 4)

P: Parentheses

E : Exponents

M: Multiplication

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Question 2

15 + 6 \times 3 \\ 15 + (6 \times 3) \\ 15 + 18 \\  = 33

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The answer is what is shown on the phone

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3 years ago
plz i need help with this its due tmrw!! (also my other most recent question is #6 of this and it would be nice for answers for
kipiarov [429]

7. <u>You have $367.50 after two years.</u>

<em>Start by converting 2.5% into a decimal (divide by 100) and multiplying by 350 to find the rate of interest per year.</em>

<em>350(0.025) = 8.75</em>

<em>Since it's for two years, multiply by two. </em>

<em>8.75 x 2 = 17.5.</em>

<em>Add it on to he original, and we have</em>

<em>350 + 17.5 = 367. 5, or $367.50 when converted back to money. </em>

8. <u>The annual interest rate is 2.4%</u>

<em>find the interest rate per year: </em>

<em>120/2.5 = 48 dollars per year. this is the interest amount, we want to find the interest rate. To do this, find what % of 2000 that 48 is equal to. </em>

<em>Set up a system of equations and cross multiply.</em>

<em />\frac{48}{2000} = \frac{x}{100}<em />

<em>2000x = 48(100) > 2000x = 4800</em>

<em>2000</em><em>/2000</em><em>x = 4800</em><em>/2000 > </em><em>x = 2.4</em>

<em>So, the interest rate is 2.4%. </em>

9.  <u>the interest paid is $300 after six months, and $600 after a year.</u>

<em>Find the interest rate, similar to problem 7. </em>

<em>3000 x 0.2 = 600. This means the interest paid is $600 a year. In six months, the total will be half, or $300.</em>

10. <u>four years.</u>

<em>Find interest rate. </em>

<em>200(0.035) = $7/year</em>

<em>Remember that value. Subtract needed from current.</em>

<em>228 - 200 = $28. </em>

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