We know:x^2+y^2+x−6y+9=0So, we complete the square as such:x^2+y^2+x−6y+9=x^2+x+y^2−6y+9=(x+1/2)^2+(y−3)^2=(1/2)^2=1/4
Take the 4cm side and the 6cm side.
If you hook them together at one end, then there's no way they can reach the ends of the 11cm side. The farthest they can reach is 10cm.
That's what choice-B says.
fhhjjkjgggujjhhfddhjfgkgfjkkllldckccjmmjgghkfgkjghgjdfdagdgjtfkgghjkkfdjkdgghjkogfkffj
Answer:
C) 40
Step-by-step explanation:
ABCD is an isosceles trapezoid
So <B = <C
x+10 = 2x - 30
-x = -40
x = 40
The answer is 4. I hope this has helped.
