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statuscvo [17]
3 years ago
15

Evaluate (3−1)³+7(6)−5²

Mathematics
2 answers:
Alekssandra [29.7K]3 years ago
7 0

Answer:

The answer is 25.

Step-by-step explanation:

likoan [24]3 years ago
3 0

Answer:

25

Step-by-step explanation:

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Given: measure 1, measure 2, measure 3, and measure 4 formed by two intersecting segments Prove: measure 1 and measure 3 are con
lesantik [10]

Step-by-step explanation:

<h3><u>Note</u>: </h3>

The text below that are formatted in bold and underlined font are the solutions to the missing boxes in your given problem.  

<h3><u>Explanation:</u></h3>

Given that ∠1, ∠2, ∠3, and ∠4 are formed by two intersecting segments, and that:

∠1 and  ∠2 form a linear pair  

∠2 and ∠3 form a linear pair  

These linear pair relationships suggest that by the Linear Pair Postulate:

<u>∠1 and ∠2 are supplementary</u>.    ⇒  Linear Pair Postulate

<u>∠2 and ∠3 are supplementary</u>.    ⇒  Linear Pair Postulate

m∠2 + m∠ 3 = 180°  ⇒  <u>Definition of supplementary angles</u>.

<u>m∠1 + m∠3  = m∠2 + m∠ 3</u>  ⇒  Substitution Property of Equality.          

m∠1  =  m∠3   ⇒  <u>Subtraction Property of Equality</u>.  

4 0
3 years ago
(1 point) (a) The Cartesian coordinates of a point are (1,1). (i) Find polar coordinates (r,θ) of the point, where r&gt;0 and 0≤
Gre4nikov [31]

Answer:

P(1, π/4)

P(-1, π/4)

P(4, 5π/6)

P(-4, 5π/6)

Step-by-step explanation:

Knowing the formulas

r = √(x²+y²)

θ = Arctg (y/x)

we have

a) P(1, 1)

i)  

r = √(1²+1²) = +1

r = +1

θ = Arctg (1/1) = π/4

P(1, π/4)

ii) r = √(1²+1²) = -1

r = -1

θ = Arctg (1/1) = π/4

P(-1, π/4)

b) P(2√3, -2)

i)  

r = √((2√3)²+(-2)²) = +4

r = +4

θ = Arctg (-2/2√3) = 5π/6

P(4, 5π/6)

ii)

r = √((2√3)²+(-2)²) = -4

r = -4

θ = Arctg (-2/2√3) = 5π/6

P(-4, 5π/6)

5 0
3 years ago
8. A going out of business sale has the entire store marked 80% off. Which of the following is equivalent to
CaHeK987 [17]

Answer:

G. 0.08

Step-by-step explanation:

It is actually 0.8 but putting a zero before 8 is fine.

0.0008=0.8

0.8000=X

3 0
3 years ago
Two perpendicular lines PQ and QR intersect at (1, -1). If the equation of PQ is x - 2y + 4 = 0, find the equation of QR.
Vinvika [58]

Answer:

2x + y - 1 = 0

Step-by-step explanation:

The equation of a line in slope- intercept form is

y = mx + c ( m is the slope and c the y- intercept )

Given

x - 2y + 4 = 0 ( subtract x + 4 from both sides )

- 2y = - x - 4 ( divide all terms by - 2 )

y = \frac{1}{2} x + 2 ← in slope- intercept form

with slope m =  \frac{1}{2}

Given a line with slope m then the slope of a line perpendicular to it is

m_{perpendicular} = - \frac{1}{m} = - \frac{1}{\frac{1}{2} } = - 2 , thus

y = - 2x + c ← is the partial equation of the perpendicular line

To find c substitute (1, - 1) into the partial equation

- 1 = - 2 + c ⇒ c = - 1 + 2 = 1

y = - 2x + 1 ← in slope intercept form

Subtract - 2x + 1 from both sides

2x + y - 1 = 0 ← in general form

5 0
4 years ago
187÷11 quanto es eso
RideAnS [48]

18/11 = 1 remainder 7

77/11=7

Answer <em>17</em>

3 0
3 years ago
Read 2 more answers
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