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shtirl [24]
3 years ago
7

Ella spent her whole allowance of $2.00, plus the 16¢ she had left over from last week, onbubble gum. If the pieces of gum had b

een a penny cheaper, she would have received threemore pieces than she did. How many pieces did she actually buy?
Mathematics
1 answer:
Tom [10]3 years ago
6 0
If x is the first price of bubble gum and
y is the number of prices she bought

$2.00+16 cents= 216 cents
216/x=y

If the first price will be 1 penny cheaper the price will be (x-1) and will get 3 more pieces of candy so will have y+3

216/(x-1)=y+3

Since both 216/x=y and 216/(x-1)=y+3 can be true in the same time this is a system of equations that will help us find y.

If 216/x=y then x=216/y
Substitute x in the other equation
216/(216/y)-1=y+3
y^2 +3y-648=0
And y could be 24 pieces and 27 pieces

Check
216cents /24 pieces= 9 cents per piece
Cheaper by 1 penny will be 8 cents
216//8=27 pieces that are 3 more than 24

Same logic for 27 pieces bought
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Answer:

a) 25% of the students exam scores fall below 55.6.

b) The minimum score for an A is 84.68.

Step-by-step explanation:

Normal Probability Distribution:

Problems of normal distributions can be solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the z-score of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.

Mean of 61 and a standard deviation of 8.

This means that \mu = 61, \sigma = 8

(a) What score do 25% of the students exam scores fall below?

Below the 25th percentile, which is X when Z has a p-value of 0.25, that is, X when Z = -0.675.

Z = \frac{X - \mu}{\sigma}

-0.675 = \frac{X - 61}{8}

X - 61 = -0.675*8

X = 55.6

25% of the students exam scores fall below 55.6.

(b) Suppose the professor decides to grade on a curve. If the professor wants 0.15% of the students to get an A, what is the minimum score for an A?

This is the 100 - 0.15 = 99.85th percentile, which is X when Z has a p-value of 0.9985. So X when Z = 2.96.

Z = \frac{X - \mu}{\sigma}

2.96 = \frac{X - 61}{8}

X - 61 = 2.96*8

X = 84.68

The minimum score for an A is 84.68.

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Answer:

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