Question

Perpendicular to the line: -5x+y=-3 going though (3,-3)

Answer 1

First you have to know what the opposite of 5x (your slope) is. That would be -1/5x. so your new y= is y=-1/5x-3. All you need to do is plug in the (3,-3) into y-y1=m(x-x1) which would end up looking like... y+3=-1/5(x-3). Then to get rid of the fraction you would multiply that whole thing by -5. you'll then get -5y-15=1(x-3) once you distribute that 1 you'll have -5y-15=1x-3... once you solve that your final answer will be..... The perpendicular line that passes through point (3,-3) is y=2/5x-3. Good luck! :)