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Leya [2.2K]
3 years ago
8

What are two zed numbers that have a sum of 3

Mathematics
1 answer:
Bumek [7]3 years ago
5 0
2+1 Or 0+3 These problems equal or sum to 3
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A farmer has enough feed to last his 15pigs for 20days. How long would the feed last if he had 10pigs​
ddd [48]

40/3 days, (13.33 days)

Step-by-step explanation:

Set up the equation, 15/20 = 10/x, and then use cross mutiply to solve it.

10 * 20 = 15x, x = 200/15 = 40/3

Why?

b/c if each pig eats the same amount of food, then the ratio between the number of pigs and days should remain constant.

5 0
3 years ago
Consuela and her three friends order 2 pizzas. Consuela cuts each pizza into 8 equal slices. She saves 2 slices of pizza for her
Akimi4 [234]
Let
x-------------->  the number of slices eating by Consuela  and her <span>three friends

we know that
[total slices]=8*2=16 slices
</span><span>[slices of pizza for her older brother]=2
x=16-2=14 slides
</span><span>Consuela and her friends share the rest of the pizza, each eating the same number of slices---------> 14/4= 3.5 slides of pizza each  (</span><span>this part is not necessary, but it is shown in a didactic way)
</span><span>
the question is 
</span><span>What fraction of the 2 pizzas is left over?
</span>[slices of pizza for her older brother]/[total slices]=2/16=1/8
<span>
the answer is (1/8)

</span>
8 0
3 years ago
Differentiate f(x) = \frac{x^{3}-4 x+1}{x^{3}}.
miv72 [106K]
f(x) = \frac{x^{3}-4 x+1}{x^{3}}\\&#10;f'(x)=\frac{(3x^2-4)\cdot x^3-(x^3-4x+1)\cdot3x^2}{x^6}\\&#10;f'(x)=\frac{x^2(3x^3-4x-3x^3+12x-3)}{x^6}\\&#10;f'(x)=\frac{8x-3}{x^4}\\&#10;
7 0
3 years ago
g A coin where the probability of heads is 0.3 is flipped 2000 times. Use the normal approximation to the binomial distribution
matrenka [14]

Title:

<h2>See the explanation.</h2>

Step-by-step explanation:

The coin is to be flipped 2000 times.

The probability of getting a head is 0.3.

It is given that, we need to get a head in between 575 and 618 times.

If we will get 575 heads then we will get (2000 - 575) tails.

Hence, if we take that we want to get n times head, then we will get (2000 - n) times tail.

The probability of not getting a head is (1 - 0.3) = 0.7.

The probability of getting n times head is ^{2000}C_n (0.3)^n \times (0.7)^{2000 - n}.

The required probability is ∑ ^{2000}C_n (0.3)^n \times (0.7)^{2000 - n}, where 575 \leq n \leq 618.

5 0
3 years ago
How do I solve this?​
Neporo4naja [7]

Answer:

v = 22

Step-by-step explanation:

Since the triangles are similar then the ratios of corresponding sides are equal, that is

\frac{BI}{MO} = \frac{BG}{MP} , substitute values

\frac{v}{33} = \frac{64}{96} ( cross- multiply )

96v = 2112 ( divide both sides by 96 )

v = 22

3 0
3 years ago
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