Answer: cos(Θ) = (√15) / 4
Explanation:
The question states:
1) sin(Θ) = 1/4
2) 0 < Θ < π / 2
3) find cos(Θ)
This is how you solve it.
1) Use the fundamental identity (in this part I use α instead of Θ, just for facility of wirting the symbols, but they mean the same for the case).

2) From which you can find:

3) Replace sin(α) with 1/4
=>

=>

4) Given that the angle is in the first quadrant, you know that cosine is positive and the final answer is:
cos(Θ) =

.
And that is the answer.
The jeep gets 22 miles per gallon...
he has 5 gallons in the tank already....
buys gas at 1.25 per gallon.....spends $ 22...so he buys 22 / 1.25 = 17.6 gallons
so he has a total of (5 + 17.6) = 22.6 gallons....at 22 miles per gallon =
22.6 * 22 = 497.2 miles <==
The answer to your question is x=-2y+4
Given:
The three equations for the three numbers are



To find:
The Pythagorean triple generated by using 4 for x and 1 for y.
Solution:
Substituting x=4 and and y=1 in the given equations, we get



In the same way find b and c.


The third number is



The required Pythagorean triple is 8, 15, and 17.
Therefore, the correct option is C.
Given:
The zeros of the polynomial are
.
Degree = 4
Leading coefficient = 1
To find:
The polynomial.
Solution:
If c is a zero of a polynomial, then (x-c) must be a factor of the polynomial.
Here, -2,4,-5, 5, are zeros of the required polynomial, so (x+2), (x-4), (x+5), (x-5) are factors of required polynomial.

![[\because a^2-b^2=(a-b)(a+b)]](https://tex.z-dn.net/?f=%5B%5Cbecause%20a%5E2-b%5E2%3D%28a-b%29%28a%2Bb%29%5D)

Using distributive property, we get


On combining like terms, we get


Here, the leading coefficient is 1. So, it is the required polynomial.
Therefore, the correct option is E.