Angle POQ and Angle UOT are identical. This also applies to angles QOP and TOU, as they are the same angles as listed before.
Answer:
y-(-1)=-2(x-(-4))
Step-by-step explanation:
Answer:
Step-by-step explanation:
Given that tank has the shape of inverted circular cone
Height = 10 feet and radius = 4 feet
After water pumped out height = 5 ft
Hence volume of water pumped out = 
Here we have r/h is constant always
Hence 
Substitute to get volume of water pumped out = 
Mass of water = density x volume = 
Work done = force x displacement
= mass x accen x displacement
Here acceleration = gravity = 32.2 ft/sec^2
Displaement = height reduced = 5 ft
W=2912(32.2)(5)\pi =468832\pi foot -pound
Answer:

Step-by-step explanation:
Given that the angle
is located in Quadrant II; and

In Quadrant II, x is negative and y is positive.

To find
, we first determine the opposite angle of
.
This will be done using the Pythagoras theorem.

Therefore:

Answer:
(x/2 , 17/2)
Step-by-step explanation:
To find a midpoint, you average the x's and average the y's. Average them by adding the x-coordinates and divide by 2. Same with the y's.
The x's are x for P1 and 0 for P2.
x+0 / 2
=x/2
This will be the x-coordinate of the midpoint. Then for the y, use 8 and 9, the y's.
8+9 / 2
= 17/2
This will be the y-coordinate of the midpoint.
The midpoint is:
(x/2 , 17/2)
You could also divide 17/2 and get 8.5 then the midpoint would be:
(x/2 , 8.5)