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taurus [48]
2 years ago
7

A museum sold 95 tickets for $1,025. Each adult ticket was $15, and each child ticket was $7. Let a represent the number of adul

t tickets sold and let c represent the number of child tickets sold. Which system of equations can be used to determine the numbers of tickets sold?
Mathematics
1 answer:
Genrish500 [490]2 years ago
4 0

Answer:

a + c = 95........eq1

15a + 7c = 1,025....eq2

Step-by-step explanation:

Given:

Total number of ticket sold = 95

Total amount collected = $1,025

Price of each adult ticket = $15

Price of each child ticket = $7

Computation:

Number of adult tickets sold = a

Number of child tickets sold = c

So,

Number of adult tickets sold + Number of child tickets sold = Total number of ticket sold

a + c = 95........eq1

and

15a + 7c = 1,025....eq2

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3/7 converted into a decimal rounded to the nearest thousand
nadya68 [22]
3/7≈0.429
I hope it will help you
6 0
3 years ago
Which of the following equations is equivalent to log(y)= 3.994 ?
Kisachek [45]

Answer:

The correct answer is option D: y = 10^{3.994}

Step-by-step explanation:

Given:  

log(y)= 3.994

Solution:

A logarithm base b of a positive number x satisfies the following definition:

y =log_b(x) => b^y =x

For x > 0, b >0, b \neq 1

Also if no base  b  is indicated, the base of the logarithm is assumed to be  10 .

Thus, in log(y)= 3.994 base b is not indicated. so its base is assumed to be 10

now

log_{10}(y)= 3.994

Then

y = 10^{3.994}

4 0
3 years ago
Two points in the Cartesian plane are A(2.00 m, −4.00 m) and B(−3.00 m, 3.00 m). Find the distance between them and their polar
Brrunno [24]

The distance between the two points is d=8.6m

The polar coordinate of A is \left(4.47,296.57\right)

The polar coordinate of B is \left(4.24,135\right)

Explanation:

The two points are A(2,-4) and B(-3,3)

The distance between two points is given by,

d=\sqrt{(2+3)^{2}+(-4-3)^{2}}\\d=\sqrt{(5)^{2}+(-7)^{2}}\\d=\sqrt{25+49}\\d=8.6

Thus, the distance between the two points is d=8.6m

The polar coordinates of A can be written as (Distance, tan^{-1} \frac{y}{x} )

Distance = \sqrt{x^{2} +y^{2} }

Substituting A(2,-4), we get,

Distance = \sqrt{2^{2} +(-4)^{2} }=\sqrt{4+16 }=4.47

tan^{-1} \frac{y}{x} =tan^{-1} \frac{-4}{2}=-63.43

To make the angle positive, let us add 360,

\theta=360-63.43=296.57

The polar coordinate of A is \left(4.47,296.57\right)

Similarly, The polar coordinate of B can be written as (Distance, tan^{-1} \frac{y}{x} )

Distance = \sqrt{x^{2} +y^{2} }

Substituting B(-3,3), we get,

Distance = \sqrt{(3)^{2}+(3)^{2}}=4.24

tan^{-1} \frac{y}{x} =tan^{-1} \frac{3}{-3}=-45

To make the angle positive, let us add 360,

\theta=180-45=135^{\circ}

The polar coordinate of B is \left(4.24,135\right)

5 0
3 years ago
1 7/11 X 2 5/6 find the product
lana66690 [7]
1 7/11  = 18/11

2 5/6  = 17/6


Product = 18/11 * 17/6

 =  306 / 66  = 51/11  = 4 7/11  Answer
3 0
3 years ago
Read 2 more answers
can put $11 of his allowance and in his savings account every week call how much money will he have after 15 weeks
dlinn [17]
11 x 15 = 165. he would have 165$
7 0
3 years ago
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