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chubhunter [2.5K]
3 years ago
8

This is the easiest question

Mathematics
1 answer:
Arturiano [62]3 years ago
5 0

Answer:  3\dfrac{2}{6}\ h

Step-by-step explanation:

Given

Rami practices his saxophone for \frac{5}{6} hour on 4 day each week

So, for a week she practices around

\Rightarrow \dfrac{5}{6}\times 4\\\\\Rightarrow \dfrac{20}{6}

Converting it into mixed fraction

\Rightarrow \dfrac{20}{6}=\dfrac{18+2}{6}\\\\\Rightarrow 3\dfrac{2}{6}\ h

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Use a proof by contradiction to show that the square root of 3 is national You may use the following fact: For any integer kirke
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Answer:

1. Let us proof that √3 is an irrational number, using <em>reductio ad absurdum</em>. Assume that \sqrt{3}=\frac{m}{n} where  m and n are non negative integers, and the fraction \frac{m}{n} is irreducible, i.e., the numbers m and n have no common factors.

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2. Let us prove now that the multiplication of an integer and a rational number is a rational number. So, r\in\mathbb{Q}, which is equivalent to say that r=\frac{m}{n} where  m and n are non negative integers. Also, assume that k\in\mathbb{Z}. So, we want to prove that k\cdot r\in\mathbb{Z}. Recall that an integer k can be written as

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Write q=x+p and let us suppose that q is a rational number. So, we get that

x=q-p.

But the subtraction or addition of two rational numbers is rational too. Then, the number x must be rational too, which is a clear contradiction with our hypothesis. Therefore, x+p is irrational.

7 0
3 years ago
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Answer:

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brainliest?

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