Answer:
Required Probability = 0.97062
Step-by-step explanation:
We are given that the weights of newborn baby boys born at a local hospital are believed to have a normal distribution with a mean weight of 4016 grams and a standard deviation of 532 grams.
Let X = weight of the newborn baby, so X ~ N(
)
The standard normal z distribution is given by;
Z =
~ N(0,1)
Now, probability that the weight will be less than 5026 grams = P(X < 5026)
P(X < 5026) = P(
<
) = P(Z < 1.89) = 0.97062
Therefore, the probability that the weight will be less than 5026 grams is 0.97062 .
Answer:
2.04 kg
Step-by-step explanation:
Answer:
t= <u>r-21</u>
7
Step-by-step explanation:
r = 7(t+3)
expanding the bracket
r = 7t + 21
bringing t to the left hand side
7t = r - 21
divide both sides by seven
t= <u>r-21</u>
7
For a 95% confidence interval, the corresponding z-score is 1.96. Therefore the deviation will by 1.96*0.5 lbs = 0.98 lbs. Therefore, the confidence interval will be (5 - 0.98, 5 + 0.98), which is (4.02, 5.98). The weight range is from 4.02 lbs to 5.98 lbs.
SQUARES BECAUSE THEY ARE IN THE MIDDLE DUMMY