X-int: none
Y-int: (0,27)
Vertex: (-3,18)
AOS: x= -3
Max & Min Value: (-3,18)
Answer: The nth term of a geometric progression is Tn = ar^(n-1)
A. 12
B. 3.6
C. -3/4
D. 0.6
Step-by-step explanation:
The nth term of a geometric progression is Tn = ar^(n-1)
Where Tn= nth term
a = first term
r = common ratio
n = number
A. a6 = (2*6) = 12
B. a6 = (0.6*6) = 3.6
C. a6 = (-1/8*6) = -3/4
D. a6 = (0.1*6) = 0.6
One 10 80 in 10 Is your answer for that question
<span>P(4, -4) ----> (-4, 7)
x- axis from 4 to -4 ; move to the left 8 units.
y-axis from -4 to 7 ; move up 11 units
</span><span>D. left 8; up 11
</span><span>C(3, -1) translated to the left 4 units and up 1 unit.
from 3 of x-axis move to the left 4 units to arrive at -1
from -1 of y-axis move up 1 unit is to arrive at 0.
(xy) </span>→ (x-4, y + 1) (-1,0) Choice D.
The function rule is -10.5
