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3 years ago

PLEASE HELP I NEED HELP ITS MULTIPLYING FRIACTIONS AND MIXED FRACTIONS

Mathematics

2 answers:

salantis [7]3 years ago

7 0

Hello! the answers are (going across) 72/90 , 6/21 , 11/24 , 100/4 , 121/12 , 175/48
if u need me to explain how i got this, feel free to message me ! have a nice day:)<3

emmasim [6.3K]3 years ago

5 0

Answer:

All answers are simplified

1) 4/5

2)2/7

3)11/24

4)25

5)10 1/12

6)3 31/48

Step-by-step explanation:

I simplified all of my answers

1) 8/2 x 9/10= 72/90= 4/5

2)3/7 x 2/3= 6/21= 2/7

3)1/2 x 11/12= 11/24

4) 4 x 6 1/4= 4/1 x 25/4= 100/4= 25/1= 25

5)3 2/3 x 2 3/4= 11/3 x 11/4= 121/12= 10 1/12

6) 7/8 x 4 1/6= 175/48= 3 31/48

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3 years ago

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Answer:

Following are the solution to the given choices:

Step-by-step explanation:

Using chebyshev's theorem :

$\to P(|(x-\mu)|\leq k \sigma)\geq 1- \frac{1}{k^2}\\\\here \\ \to \mu=28.75\\\\ \to \sigma=4.44$

In point a)

$\to |(x-\mu)|= |20.17-28.75|=8.58 and \sigma=4.44 \\\\so, \\k= \frac{ |(x-\mu)| }{\sigma}$

$= \frac{8.58}{4.44} \\\\ =1.9 \\\\ =2$

$value= (1- \frac{1}{k^2}) \times 100 \% =75\%$

In point b)

$\to (1- \frac{1}{k^2}) \times 100 \% =84\% \\\\\to (1- \frac{1}{k^2})=0.84 \\\\\to \frac{1}{k^2} =0.16 \\\\\to \frac{1}{k}=0.4\\\\ \to k=2.5 \\\\\to |(x-\mu)| \leq k \sigma \\\\= |(x-\mu)|\leq 2.5 \times 4.44 \\\\ = |(x-\mu)|\leq 1.11 \\\\ = (28.75\pm 11.1) \\\\\to \text{fares lies between}(17.65,39.85)$