Answer:
cos(60) = 12
Step-by-step explanation:
I don't understand the question, but that is the only logical answer choice.
Not really sure but hope this helps
1. The surface that will be exposed to the rain is the lateral surface of the cylinder and the hemisphere.
2. The lateral area of the cylinder is a rectangle with height equal to the height of the cylinder and width equal to the circumference of the base of the cylinder.
3. the circumference of the base = 2

r=2*

*5=10

so the lateral area = 10

*h=10

*40=400

(

)
4. The surface area of a sphere is

so the surface of the hemisphere =

(

)
5. Total area exposed = 450
Answer:
'A' is true; theoretically, 50% of the data items reside between the first and third quartiles (40 and 67.5)
Step-by-step explanation:
Range is 84-28 which is 56
Median is 51
1.5 x Interquartile Range (IQR) = 1.5(67.5-40) which equals 41.25
Q1 is 40
Q1 - IQR = -1.25
Low outliers are below -1.25 - 41.25; there are not data items below -42
That would be a true statement.