Answer:
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Answer:
x ≤ 2
Step-by-step explanation:
If you referencing ">=" as greater than or equal to, follow the solution below:
Solve:
3x - 6 + 2 ≥ 5x - 8
Combine like terms.
3x - 4 ≥ 5x - 8
Subtract 5x from both sides.
-2x - 4 ≥ -8
Add 4 to both sides.
-2x ≥ -4
Divide both sides by -2, while flipping the inequality as well since you're dividing by a negative number.
x ≤ 2
Your answer would be x ≤ 2
Answer:
x=2
Step-by-step explanation:
logx (2x)^3 = 6
We can rewrite without the exponent
3 logx (2x) = 6
Divide by 3
3/3 logx (2x) = 6/3
logx (2x) = 2
Raise each side to the base x
x^ logx (2x) =x^ 2
2x = x^2
Subtract 2x from each side
2x-2x = x^2 -2x
0 = x^2 -2x
Factor an x
0 = x(x-2)
Using the zero product property
x =0 x-2 =0
x =0 x=2
We cannot have a base of 0, so x cannot equal 0
x=2
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