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Alja [10]
3 years ago
7

Find the measure of 0. (to the nearest tenth). A) 36.9 B) 38.7 C) 51.3 D) 53.1

Mathematics
2 answers:
BartSMP [9]3 years ago
8 0

Answer:

A) 36.9

Step-by-step explanation:

took the test :)

kupik [55]3 years ago
4 0

Answer:

B) 38.7

Step-by-step explanation:

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One tank is filling at a rate of 5 gallon per 7 hour. A second tank is 8 10
seraphim [82]

Answer:

the second one

Step-by-step explanation:

8 0
3 years ago
BC = 4x + 2 AB = 8x + 8 and AC = 22 Find BC
Scilla [17]

Answer:

BC = 6.8

Step-by-step explanation:

The distance from A to B, then from B to C, is the same distance as from A to C.

Thus,

AB + BC = AC

AB = 8x + 8

BC = 4x + 2

AC = 22

AB + BC = AC

(8x + 8) + (4x + 2) = 22

Expanding the parenthesis:

8x + 8 + 4x + 2 = 22

8x + 4x + 8 + 2 = 22

12x + 12 = 22

Subtracting 12 from both sides:

12x = 10

Dividing both sides by 12:

x = 10/12 = 1.2

x = 1.2

We're looking for BC. As we know,

BC = 4x + 2

Let's now put in x = 1.2 into this equation:

BC = 4x + 2

BC = 4 * 1.2 + 2

Since 4 * 1.2 is 4.8:

BC = 4.8 + 2

BC = 6.8

Answer: BC = 6.8

8 0
3 years ago
How do I get the answer for exponents? Please explain step by step to get marked!
ioda

Answer:

4900

Step-by-step explanation:

70^2 means 70*70

70*70=4900

3 0
3 years ago
Read 2 more answers
PLZ PLZ HELP ME .
Ket [755]

Answer:

he bought the t shirt for rs 1880

7 0
3 years ago
Pleaseee helppp with thissss asapppp
Natasha2012 [34]

As we know that the standard equation of circle is {\bf{(x-h)^{2}+(y-k)^{2}=r^{2}}} , where <em>r</em> is the radius of circle and centre at <em>(h,k) </em>

Now , as the circle passes through <em>(2,9)</em> so it must satisfy the above equation after putting the values of <em>h</em> and <em>k</em> respectively

{:\implies \quad \sf \{2-(-1)\}^{2}+(9-5)^{2}=r^{2}}

{:\implies \quad \sf (3)^{2}+(4)^{2}=r^{2}}

{:\implies \quad \sf 9+16=r^{2}}

After raising ½ power to both sides , we will get <em>r = +5 , -5</em> , but as radius can never be -<em>ve</em> . So <em>r = +</em><em>5</em><em> </em>

Now , putting values in our standard equation ;

{:\implies \quad \sf \{x-(-1)\}^{2}+(y-5)^{2}=(5)^{2}}

{:\implies \quad \bf \therefore \quad \underline{\underline{(x+1)^{2}+(y-5)^{2}=25}}}

<em>This is the required equation of </em><em>Circle</em>

Refer to the attachment as well !

8 0
2 years ago
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