HELP PLEASE!!!

Mathematics

1 answer:

nikdorinn [45]3 years ago

6 0

Answer:

Option A

Step-by-step explanation:

$R = (\frac{V_f-Vi}{V_i} )100$

where,

$V_f$ is the final value

$V_i$ if the initial value

R is the investors rate of return

so,

$R = (\frac{V_f-Vi}{V_i} )100\\\\R=(\frac{1500-1700}{1700})100 \\\\R=(\frac{-200}{1700})100 \\\\R=-11.8\\$

so the investors rate of return is -11.8%

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The weights of college football players are normally distributed with a mean of 200 pounds and a standard deviation of 50 pounds

Feliz [49]

Answer:

0.3811 = 38.11% probability that he weighs between 170 and 220 pounds.

Step-by-step explanation:

When the distribution is normal, we use the z-score formula.

In a set with mean $\mu$ and standard deviation $\sigma$ , the zscore of a measure X is given by:

$Z = \frac{X - \mu}{\sigma}$

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

In this question, we have that:

$\mu = 200, \sigma = 50$