Answer:
C≈59.19
Step-by-step explanation:
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Answer:
A score of 150.25 is necessary to reach the 75th percentile.
Step-by-step explanation:
Problems of normal distributions can be solved using the z-score formula.
In a set with mean
and standard deviation
, the zscore of a measure X is given by:

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.
A set of test scores is normally distributed with a mean of 130 and a standard deviation of 30.
This means that 
What score is necessary to reach the 75th percentile?
This is X when Z has a pvalue of 0.75, so X when Z = 0.675.




A score of 150.25 is necessary to reach the 75th percentile.
33 is the answer to that question
y - 6 = 4(1 - 4)
y - 6 = 4 - 16
y - 6 = -12
y = -12 + 6
y = -6
This is a horizontal line through the point (0, -6). See below.
Answer:

Step-by-step explanation:
we know that
The simple interest formula is equal to
where
A is the Final Investment Value
P is the Principal amount of money to be invested
r is the rate of interest
t is Number of Time Periods
in this problem we have
The inequality that represented this situation is

substitute the values and solve for t


![t \leq [(7,020/4,500)-1]/0.03](https://tex.z-dn.net/?f=t%20%5Cleq%20%5B%287%2C020%2F4%2C500%29-1%5D%2F0.03)
