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Mamont248 [21]
3 years ago
13

if you could respond with the work shown that would be amazing! i rate people very nicely!! this is due before 7 AM EST time :)

Mathematics
1 answer:
yulyashka [42]3 years ago
4 0

Answer:

35ft squared

Step-by-step explanation:

First lets try solving the rectangular middle part

Width is 3 ft

Height is 5ft + 4ft = 9ft

3*9ft= 27ft. This is area of middle rectangular section

For the triangle, we subtract 3 from the rectangle from 11ft and divide by 2 because the two triangle on the edges are the same.

11-3=8

8/2=4

Triangle area formula = Base*Height / 2

4*4/2

16/2

4ft squared

and the other triangles area is also 4ft squared because they are congruent. So you add all the sections of the area up

27ft+4ft+4ft=35ft squared

35ft squared is the answer.

Hope this helps :)

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How many kids are on the planet 100 points to who ever does the best meme
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Answer:

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The points on the number line represent the value of your different numbers.Which pojnt best represent the value of square root
wariber [46]

Answer:

The answer is B. Point B

Step-by-step explanation:

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4 0
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Help and show all work please
Anarel [89]

Answer:

1-3

2-8.9

3-6.3

4-26

5-7.8

6-17

7-10

8-32

9-7.9

10-13.2

11- is a right triangle

12- is not a right triangle

13- is a right triangle

14- is not a right triangle

15- is a right triangle

16- is not a right triangle

Step-by-step explanation:

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7 0
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Write the expression 6a in words
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4 years ago
The heights of women in the USA are normally distributed with a mean of 64 inches and a standard deviation of 3 inches.
Rainbow [258]

Answer:

(a) 0.2061

(b) 0.2514

(c) 0

Step-by-step explanation:

Let <em>X</em> denote the heights of women in the USA.

It is provided that <em>X</em> follows a normal distribution with a mean of 64 inches and a standard deviation of 3 inches.

(a)

Compute the probability that the sample mean is greater than 63 inches as follows:

P(\bar X>63)=P(\frac{\bar X-\mu}{\sigma/\sqrt{n}}>\frac{63-64}{3/\sqrt{6}})\\\\=P(Z>-0.82)\\\\=P(Z

Thus, the probability that the sample mean is greater than 63 inches is 0.2061.

(b)

Compute the probability that a randomly selected woman is taller than 66 inches as follows:

P(X>66)=P(\frac{X-\mu}{\sigma}>\frac{66-64}{3})\\\\=P(Z>0.67)\\\\=1-P(Z

Thus, the probability that a randomly selected woman is taller than 66 inches is 0.2514.

(c)

Compute the probability that the mean height of a random sample of 100 women is greater than 66 inches as follows:

P(\bar X>66)=P(\frac{\bar X-\mu}{\sigma/\sqrt{n}}>\frac{66-64}{3/\sqrt{100}})\\\\=P(Z>6.67)\\\\\ =0

Thus, the probability that the mean height of a random sample of 100 women is greater than 66 inches is 0.

8 0
3 years ago
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