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ExtremeBDS [4]
3 years ago
9

Ms. Jones bought volleyball tickets online. The ticket company charges a

Mathematics
1 answer:
Pachacha [2.7K]3 years ago
3 0

Answer:

3 tickets

Step-by-step explanation:

$23.55-$1.50= $22.05 / $7.35 =  3

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What is the length of the hypotenuse in a right triangle with legs of length 7 and 24?
Fiesta28 [93]
A² + b² = c²   a and b are the legs and c is the hypotenuse.

7² + 24² = c²

49 + 576 = c²

625 = c²

√625 = √c²

25 = c

hope that helps, God bless!

4 0
2 years ago
Estimate the quotient to the nearest whole number by using compatible numbers 32.44 ÷ 4.36
GarryVolchara [31]
I'm pretty sure its 7
7 0
3 years ago
You throw a ball up and its height h can be tracked using the equation h=2x^2-12x+20.
postnew [5]

<em><u>This problem seems to be wrong because no minimum point was found and no point of landing exists</u></em>

Answer:

1) There is no maximum height

2) The ball will never land

Step-by-step explanation:

<u>Derivatives</u>

Sometimes we need to find the maximum or minimum value of a function in a given interval. The derivative is a very handy tool for this task. We only have to compute the first derivative f' and have it equal to 0. That will give us the critical points.

Then, compute the second derivative f'' and evaluate the critical points in there. The criteria establish that

If f''(a) is positive, then x=a is a minimum

If f''(a) is negative, then x=a is a maximum

1)

The function provided in the question is

h(x)=2x^2-12x+20

Let's find the first derivative

h'(x)=4x-12

solving h'=0:

4x-12=0

x=3

Computing h''

h''(x)=4

It means that no matter the value of x, the second derivative is always positive, so x=3 is a minimum. The function doesn't have a local maximum or the ball will never reach a maximum height

2)

To find when will the ball land, we set h=0

2x^2-12x+20=0

Simplifying by 2

x^2-6x+10=0

Completing squares

x^2-6x+9+10-9=0

Factoring and rearranging

(x-3)^2=-1

There is no real value of x to solve the above equation, so the ball will never land.

This problem seems to be wrong because no minimum point was found and no point of landing exists

3 0
3 years ago
Find the center and radius of the circle with the given equation. Then select the correct graph of the equation.
likoan [24]

Answer:

Step-by-step explanation:

In order to find the center and the radius of this circle, you have to complete the square on it. And only for the x-terms, because the y term is squared and there is no other y term. We'll get to that in a second.

Take half the linear x-term, square it and add it to both sides. Our linear term is 10. Half of 10 is 5, and 5 squared is 25. We add 25 to both sides:

The reason we do this is to create a perfect square binomial inside that set of parenthesis. Simplifying the right side as well gives us:

This tells us that the center is (-5, 0). Remember when I said we would get back to the y terms? Because there was only a y-squared and no other y terms, that is the same as writing the equation as

The radius is the square root of the constant. So the radius is 6.

D is the graph you want.

3 0
2 years ago
4. At $2.329 per gallon for regular
rosijanka [135]

Answer:

$20.47

hope that's right.

7 0
3 years ago
Read 2 more answers
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