All categories

3 years ago

Anmol got 60 marks out of 80 marks in mathematics what percent marks did he get

Mathematics

1 answer:

Kay [80]3 years ago

3 0

Answer:

75%

Step-by-Step Explanation:

There are two ways to go about this.

1) We can simply put it as a fraction = 60/80.

Then since a fraction sign also means division, we divide 60 by 80 = 0.75

Then to change a decimal into a percentage, we multiply by 100% = 75%

So our answer is 75%

2) We can simply it after it is put into a fraction = 60/80 = 3/4

It should be common knowledge that 3/4 is 75% depending on what grade you are in.

But there you have it, whichever way you prefer, the answer is always 75%.

You might be interested in

sean and morgan walked from the same location sean walked 5 1/2 blocks north and 3 1/4 blocks east morgan walked 3 1/4 blocks ea

Yakvenalex [24]

Answer:

Step-by-step explanation:

5 1/2 + 4 1/2 = 10

4 0

3 years ago

Ali was paid $75 for mowing a neighbor's yard. This is one fourth the amount of money she earned all summer. How much did Ali ea

Ratling [72]

Answer:

75x4=300

Step-by-step explanation:

5 0

2 years ago

A dolphin was swimming 20 feet below the surface of the water. It descended 8 feet to catch a fish. What integer represents its

Nimfa-mama [501]

-28. It’s underwater which is -20 and went -8 more feet down.

3 0

3 years ago

Find the directional derivative of at the point (1, 3) in the direction toward the point (3, 1). g

Anika [276]

Complete Question:

Find the directional derivative of g(x,y) = $x^2y^5$ at the point (1, 3) in the direction toward the point (3, 1)

Answer:

Directional derivative at point (1,3), $D_ug(1,3) = \frac{162}{\sqrt{8} }$

Step-by-step explanation:

Get $g'_x$ and $g'_y$ at the point (1, 3)

g(x,y) = $x^2y^5$

$g'_x = 2xy^5\\g'_x|(1,3)= 2*1*3^5\\g'_x|(1,3) = 486$

$g'_y = 5x^2y^4\\g'_y|(1,3)= 5*1^2* 3^4\\g'_y|(1,3)= 405$

Let P = (1, 3) and Q = (3, 1)

Find the unit vector of PQ,

$u = \frac{\bar{PQ}}{|\bar{PQ}|} \\\bar{PQ} = (3-1, 1-3) = (2, -2)\\{|\bar{PQ}| = \sqrt{2^2 + (-2)^2}\\$

$|\bar{PQ}| = \sqrt{8}$

The unit vector is therefore:

$u = \frac{(2, -2)}{\sqrt{8} } \\u_1 = \frac{2}{\sqrt{8} } \\u_2 = \frac{-2}{\sqrt{8} }$

The directional derivative of g is given by the equation:

$D_ug(1,3) = g'_x(1,3)u_1 + g'_y(1,3)u_2\\D_ug(1,3) = (486*\frac{2}{\sqrt{8} } ) + (405*\frac{-2}{\sqrt{8} } )\\D_ug(1,3) = (\frac{972}{\sqrt{8} } ) + (\frac{-810}{\sqrt{8} } )\\D_ug(1,3) = \frac{162}{\sqrt{8} }$

8 0

2 years ago

What is the midpoint of the segment shown below? (-2, 3) (10, 3)

ozzi

The two points are (-2,3) and (10,3)

The x coordinates of each point are -2 and 10. Add them up and we get -2+10 = 8. Cut this in half to get 8/2 = 4
This is the x coordinate of the midpoint

Do the same for the y coordinates.
Add them up: 3+3 = 6.
Divide by 2: 6/2 = 3
This is the y coordinate of the midpoint

The midpoint is therefore (4,3)

8 0

3 years ago

Read 2 more answers

Anmol got 60 marks out of 80 marks in mathematics what percent marks did he get​

Anmol got 60 marks out of 80 marks in mathematics what percent marks did he get