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3 years ago

Find the product of 3y^3(6y^2-9y+6)

Mathematics

1 answer:

Valentin [98]3 years ago

7 0

Answer: Simplified expression- $18y^{5} - 27y^{4} + 18y^{3}$

Step-by-step explanation: You get the product by simplifying it.

I tried my best, I hope this it what you were looking for:)

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A sum amount to rupees 34476 in two and a half years at 4% CI. the sum is

Kruka [31]

Given:

Amount = Rs. 34476

Rate of compound interest = 4%

Time = $2\dfrac{1}{2}=2.5$ years

To find:

The principal value.

Solution:

Formula for amount is

$A=P\left(1+\dfrac{r}{100}\right)^t$

Where, P is principal value, r is rate of interest and t is time in years.

Putting the given values, we get

$34476=P\left(1+\dfrac{4}{100}\right)^{2.5}$

$34476=P\left(1+0.04\right)^{2.5}$

$34476=P\left(1.04\right)^{2.5}$

$\dfrac{34476}{\left(1.04\right)^{2.5}}=P$

Now,

$P=31256.0090$

$P\approx 31256$

Therefore, the value of sum or principal value is Rs.31256.

6 0

3 years ago

I got a feeling I’m wrong

Sunny_sXe [5.5K]

Answer:

You are absolutely correct.

Step-by-step explanation:Equilateral, meaning all sides are the same size, and acute, meaning all angles are lower than 90 degrees. You are correct.

8 0

3 years ago

Read 2 more answers

Anyone help me with this please!!

Vera_Pavlovna [14]

Answer;
35, 70, and 77

4 0

2 years ago

SOS WHAT IS THE SQUARE ROOT OF 144/256?

tangare [24]

The square root is $\sqrt{\frac{144}{256}} = \frac{3}{4}$ Just square the top and bottom of the fraction. $\sqrt{144} = 12$ and $\sqrt{256} = 16$ so we have 12/16 and then we reduce to 3/4