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Anettt [7]
3 years ago
5

Find the product of 3y^3(6y^2-9y+6)

Mathematics
1 answer:
Valentin [98]3 years ago
7 0

Answer: Simplified expression- 18y^{5} - 27y^{4} + 18y^{3}

Step-by-step explanation: You get the product by simplifying it.

I tried my best, I hope this it what you were looking for:)

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Can someone plz help me?
ivann1987 [24]

Answer: The correct answer is Choice C.

Step-by-step explanation: In order to solve this problem you need to look at the equation’s parts.

The first part is multiplying 5 by the contents of the parenthesis. So, 5(2x-2) equals 10x - 10. Now, but the equation together and simplify it:

10x - 10 + 10x =

20x - 10

3 0
4 years ago
6 cm<br>What is the area of this shape?<br>5 cm<br>8 cm​
erica [24]
Where is the shape or do you have a picture of it
7 0
3 years ago
Charmaine is on the swim team. Each week she swims a total of 6,000 meters. How many kilometers does she swim each week?
alex41 [277]

Answer:

1000m = 1 km

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3 0
3 years ago
Read 2 more answers
Need help please and thank you.
AURORKA [14]
X+3=61
x=61-3=58

58+37=95
180-95=85

so x=58 and y=85
5 0
2 years ago
Can someone help me with this problem ​
Alex_Xolod [135]

Answer:

<h2>A = 20</h2><h2>P = 6√10</h2>

Step-by-step explanation:

The formula of a distance between two points:

d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}

A(-3, 0) , B(3, 2)

AB=\sqrt{(3-(-3))^2+(2-0)^2}=\sqrt{6^2+2^2}=\sqrt{36+4}=\sqrt{40}=\sqrt{4\cdot10}=\sqrt4\cdot\sqrt{10}=2\sqrt{10}

A(-3, 0), D(-2, -3)

AD=\sqrt{(-2-(-3))^2+(-3-0)^2}=\sqrt{1^2+(-3)^2}=\sqrt{1+9}=\sqrt{10}

AB = CD and AD = BC

The area of a rectangle:

A=(AB)(AD)

Substitute:

A=(2\sqrt{10})(\sqrt{10})=(2)(10)=20

The perimeter of a rectangle:

P=2(AB+AD)

Substitute:

P=2(2\sqrt{10}+\sqrt{10})=2(3\sqrt{10})=6\sqrt{10}

4 0
3 years ago
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