Given:
The equation of a circle is
A tangent line l to the circle touches the circle at point P(12,5).
To find:
The gradient of the line l.
Solution:
Slope formula: If a line passes through two points, then the slope of the line is
Endpoints of the radius are O(0,0) and P(12,5). So, the slope of radius is
We know that, the radius of a circle is always perpendicular to the tangent at the point of tangency.
Product of slopes of two perpendicular lines is always -1.
Let the slope of tangent line l is m. Then, the product of slopes of line l and radius is -1.
Therefore, the gradient or slope of the tangent line l is 
.
Answer:
x = 28
Step-by-step explanation:
If AB and CD are the straight lines, sum all the angles formed at a point lying on this line will be 180°.
m∠COE + m∠EOF + m∠FOB + m∠BOD = 180° [Angles at a point O on line AB]
3x + x + (x + 12) + m∠BOD = 180°
m∠BOD = 180° - (5x + 12)
Similarly, m∠AOD + m∠AOC = 180°
152° + m∠AOC = 180°
m∠AOC = 28°
Since, ∠AOC and ∠BOD are the vertical angles,
m∠AOC = m∠BOD
180° - (5x + 12)° = 28°
5x + 12 = 180 - 28
5x = 140
x = 28
The range is <span>is greater for data set 2.
- This is because it goes from 21-34 in the first set and 12-36 in the second.
The mean is greater for data set 2.
- This is because the first mean is 27.4 and the second is 28.05. </span>
Yes! You’re on the right track! You followed it perfectly!
Parentheses
Exponent
Multiplication
Division
Addition
Subtraction
Well done!
Answer:
36/48 or 6/8 or 3/4 or .75
Step-by-step explanation:
6^2/ [(2+4)*2^3]
6^2/ [ ( 6)*2^3]
36/[(6)*8]
36/48
