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3 years ago

Find the midpoint of (-7,-2) AND (1,7)

Mathematics

1 answer:

Gala2k [10]3 years ago

5 0

Answer:

(-3 ,2.5)

Step-by-step explanation:

midpoint formula is

x1+x2 y1+y2

(___ , _____ )

2 2

(-7,-2) -7 is x1 i.e the first x point and -2 is y1 1st y point

(1,7) 1 is x2 i.e the second x point and 7 is y2 the second y point

now we use input the numbers to the formula

-7+1 -2+7

(____ , --------)

2 2

we the signs are different you subtract and use sign of greater number

-6 5

__ , ___

2 2

Now you divide

and here is the ordered pair for midpoint.

(-3 ,2.5)

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Answer:

Step 1: The estimate the proportion of tenth graders reading at or below the eighth grade level is 0.2.

Step 2: The 99% confidence interval for the population proportion of tenth graders reading at or below the eighth grade level is (0.181, 0.219).

Step-by-step explanation:

In a sample with a number n of people surveyed with a probability of a success of $\pi$ , and a confidence level of $1-\alpha$ , we have the following confidence interval of proportions.

$\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}$

In which

z is the z-score that has a p-value of $1 - \frac{\alpha}{2}$ .

Suppose a sample of 2845 tenth graders is drawn. Of the students sampled, 2276 read above the eighth grade level.

So 2845 - 2276 = 569 read below, and the estimate of the proportion of tenth graders reading at or below the eighth grade level is:

$\pi = \frac{569}{2845} = 0.2$ , and the answer to step 1 is 0.2.

The sample size is $n = 2845$

99% confidence level

So $\alpha = 0.01$ , z is the value of Z that has a p-value of $1 - \frac{0.01}{2} = 0.995$ , so $Z = 2.575$ .

The lower limit of this interval is:

$\pi - z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.2 - 2.575\sqrt{\frac{0.2*0.8}{2845}} = 0.181$

The upper limit of this interval is:

$\pi + z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.2 + 2.575\sqrt{\frac{0.2*0.8}{2845}} = 0.219$

The 99% confidence interval for the population proportion of tenth graders reading at or below the eighth grade level is (0.181, 0.219).

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Pic 1

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------------
pic2

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