Question

Abundance of the different bases in the human genome. Results on the human genome published in Science (Science 291:1304-1350 [2001]) indicate that the haploid human genome consists of 2.91 gigabase pairs (2.91 x 109 base pairs) and that 27% of the bases in human DNA are A. Calculate the number of A, T, G, and C residues in a typical human cell.

Answer 1

Answer:

A typical Human Cells=$3.1428*10^9$ residues.

T typical Human Cells=$3.1428*10^9$ residues.

G typical Human cells=$2.6772*10^{9}$ residues.

C typical Human cells=$2.6772*10^{9}$ residues.

Explanation:

Given:

Number of human genome in pairs=2.91*10^9 base pair

Number of Human genome single bases=$2*2.91*10^{9} =5.82*10^{9}$ bases

We know that human genome are diploid, Total Human genomes will bases will be $2* 5.82*10^{9}=1.164*10^{10}$ bases

Since A is 27%:

A typical Human cells=$0.27*1.164*10^{10}$

A typical Human Cells=$3.1428*10^9$ residues.

The Number of T and A residues are same in human genome. So,

T typical Human cells=$3.1428*10^9$ residues.

Since A and T combined form 54% of human genome then G and C form 46% combined and 23% each.

G typical Human cells=$0.23*1.164*10^{10}$

G typical Human cells=$2.6772*10^{9}$ residues.

The Number of G and C residues are same in human genome. So,

C typical Human cells=$2.6772*10^{9}$ residues.