Answer:
3/4
Area of the small triangle/Area of larger triangle=3/4
Area of the small triangle/Area of larger triangle=(1/2×base of small triangle×length)/(1/2×base of larger triangle×height)
3/4=(1/2×base of small triangle×height)/(1/2×base of larger triangle×height)
Since the length of the triangle are equal the base ratio of the two triangles is the same as area ratio.
Answer:
it create angle CFD and angle EFD
Step-by-step explanation:
i believe it create that because after the one triangle gets broken into 2, its saying the two smaller angles next to the f.
Answer: A = ≈28.55 cm²
Step-by-step explanation:
It is drawn as if it should be a triangle minus a rectangle with an area of
½(10)(13) - (7)(6) = 23 cm²
However it is not to scale.
The angle on the right side is
θ = arctan10/13 = 37.56859...°
Meaning the right triangle has a height of
h = 4tan37.56859 = 3.07692 cm
So the right triangle has an area of
Ar = ½(3.07692)(4) = 6.15384... cm²
The left hand side consists of a triangle over a rectangle
The height of the triangle is 4, the base is is 4/tan37.56859 = 5.2 cm
so the left area is
(2)(6) + ½(5.2)(4) = 22.4 cm²
So the sum of the areas of the two enclosed shapes is
A = 22.4 + 6.15384... = 28.55384... ≈28.55 cm²
Answer:
(3a-1)(3a+1)
Step-by-step explanation:
We can quickly see with this problem that it is the difference of two squares as 9a^2 is (3a)^2 and 1 is 1^2 and therefore can factorise quickly using this rule.
x^2-y^2 = (x-y)(x+y) where x = 3a and y = 1
Complete Question
A person standing 213 feet from the base of a church observed the angle of elevation to the church's steeple to be 33 ∘. Find the height of the church
Answer:
138.3 ft
Step-by-step explanation:
We solve this question above using using the Trigonometric function of Tangent.
tan θ = Opposite/Adjacent
Where:
Opposite = Height of the church = x
Adjacent = Distance for the base of the church = 213ft
Angle of elevation θ = 33°
Hence:
tan 33 = x /213 ft
Cross Multiply
x = tan 33 × 213 ft
x = 138.32381735 ft
x = Opposite Approximately = 138.3 ft
Therefore, the height of the church = 138.3 ft
