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madreJ [45]
3 years ago
11

Whats the answer and show work -7x-2=24-9x

Mathematics
2 answers:
sladkih [1.3K]3 years ago
8 0

Answer:

x=11 there is my work. Your welcome

schepotkina [342]3 years ago
4 0

Answer:

-7x -2 = 24 -9x

+9x     =       +9x Add 9x both side to bring the like terms together

2x - 2 =   24

      +2 = +2 Add 2 both side to isolate the variable

2x = 26    Divide both side by 2, to get the value of x

x  =  13

Step-by-step explanation:

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Keith_Richards [23]
If the car is traveling at 50meters per second then you need to multiply 50 by 60 to get how many meters a minute then multiply that number by 60 to get meters per hour then take that number and divide it by 1000 to get kilometers per hour.







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3 0
2 years ago
Which of the following is equivalent to the expression below for x≠6?
nata0808 [166]

Answer:

The fourth answer choice is the correct one:  2(x - 3)

Step-by-step explanation:

2x²-18x+36/x-6 should be factored, as follows:

2(x²-9x+18) / (x-6) = 2(x - 3) (x - 6) / (x - 6)

Substituting x = 6 would result in division by zero and is thus not allowed.

Remembering this, we can reduce 2(x - 3) (x - 6) / (x - 6) to 2(x - 3) for x≠6.

6 0
3 years ago
What decimal represents 6×1,000+2×10+3×1/10+5×1/1,000
Contact [7]

6 × 1,000 = 6,000

2 × 10 = 20

3 × 1/10 = 3/10 = 0.3

5 × 1/1,000 = 5/1,000 = 0.005

6 × 1,000 + 2 × 10 + 3 × 1/10 + 5 × 1/1,000 = 6,020.305

4 0
3 years ago
1-What is the sum of the series? ​∑j=152j​ Enter your answer in the box.
tangare [24]

Answer:

Please see the Step-by-step explanation for the answers

Step-by-step explanation:

1)

∑\left \ {{5} \atop {j=1}} \right. 2j

The sum of series from j=1 to j=5 is:

∑ = 2(1) + 2(2) + 2(3) + 2(4) + 2(5)

  =  2 + 4 + 6 + 8 + 10

∑ = 30

2)

This question is not given clearly so i assume the following series that will give you an idea how to solve this:

∑\left \ {{4} \atop {k=1}} \right. 2k²

The sum of series from k=1 to j=4 is:

∑ = 2(1)² + 2(2)² + 2(3)² + 2(4)²

  = 2(1) + 2(4) + 2(9) + 2(16)

  =  2 + 8 + 18 + 32

∑ = 60

∑\left \ {{4} \atop {k=1}} \right. (2k)²

∑ = (2*1)² + (2*2)² + (2*3)² + (2*4)²

  = (2)² + (4)² + (6)² + (8)²

  = 4 + 16 + 36 + 64

∑ = 120

∑\left \ {{4} \atop {k=1}} \right. (2k)²- 4

∑ = (2*1)²-4 + (2*2)²-4 + (2*3)²-4 + (2*4)²-4

  = (2)²-4 + (4)²-4 + (6)²-4 + (8)²-4

  = (4-4) + (16-4) + (36-4) + (64-4)

  = 0 + 12 + 32 + 60

∑ = 104

∑\left \ {{4} \atop {k=1}} \right. 2k²- 4

∑ = 2(1)²-4 + 2(2)²-4 + 2(3)²-4 + 2(4)²-4

  = 2(1)-4 + 2(4)-4 + 2(9)-4 + 2(16)-4

  = (2-4) + (8-4) + (18-4) + (32-4)

  = -2 + 4 + 14 + 28

∑ = 44

3)

∑\left \ {{6} \atop {k=3}} \right. (2k-10)

∑ = (2×3−10) + (2×4−10) + (2×5−10) + (2×6−10)  

  = (6-10) + (8-10) + (10-10) + (12-10)

  = -4 + -2 + 0 + 2  

∑ = -4

4)

1+1/2+1/4+1/8+1/16+1/32+1/64

This is a geometric sequence where first term is 1 and the common ratio is 1/2 So

a = 1

This can be derived as

1/2/1 = 1/2 * 1 = 1/2

1/4/1/2 = 1/4 * 2/1 = 1/2

1/8/1/4 = 1/8 * 4/1  = 1/2

1/16/1/8 = 1/16 * 8/1  = 1/2

1/32/1/16 = 1/32 * 16/1  = 1/2

1/64/1/32 = 1/64 * 32/1  = 1/2

Hence the common ratio is r = 1/2

So n-th term is:

ar^{n-1} = 1(\frac{1}{2})^{n-1}

So the answer that represents the series in sigma notation is:

∑\left \ {{7} \atop {j=1}} \right. (\frac{1}{2})^{j-1}

5)

−3+(−1)+1+3+5

This is an arithmetic sequence where the first term is -3 and the common difference is 2. So  

a = 1

This can be derived as

-1 - (-3) = -1 + 3 = 2

1 - (-1) = 1 + 1 = 2

3 - 1 = 2

5 - 3 = 2

Hence the common difference d = 2

The nth term is:

a + (n - 1) d

= -3 + (n−1)2

= -3 + 2(n−1)

= -3 + 2n - 2

= 2n - 5

So the answer that represents the series in sigma notation is:

∑\left \ {{5} \atop {j=1}} \right. (2j−5)

6 0
3 years ago
Evaluate. 5(-6) = _____
Brums [2.3K]

ANSWER

Your answer is -30

3 0
3 years ago
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