Question

The Key Club is having a fundraising dinner for charity. The venue that holds a maximum of 500 people will

Answer 1

Answer:

$\dfrac{\ 1000+\ 20x}{x} \leq \ 25$

Minimum 200 people other than the 2 charity representatives.

Step-by-step explanation:

Given that:

The venue can hold a maximum of 500 people.

Cost of venue = $1000

Per person cost for food = $20

Two charity representatives get to attend the dinner for free.

To find:

The inequality and to determine how many people must come to keep costs at most $25.

Solution:

Let the number of people attending the dinner = $x$

Cost of food for $x$ people = $\ 20x$

Total cost = $1000 + $\ 20x$

Cost per person = Total cost divided by Number of people attending the dinner.

As per question statement:

$\dfrac{\ 1000+\ 20x}{x} \leq \ 25\\\Rightarrow 1000+20x\leq25x\\\Rightarrow 1000 \leq 5x\\\Rightarrow x\geq 200$

Therefore, the answer is:

Minimum 200 people other than the 2 charity representatives should attend the dinner.