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2 years ago

7

The emergency brake cable in a truck parked on a steep hill breaks and the truck starts rolling down the hill. The distance in f

eet, , that the truck rolls is represented by the function =()=0.52
. Using this function, find out how far the truck will roll after 9 seconds. (Enter your answer as a decimal)

The truck will roll
(Answer)
feet in 9 seconds.

1 answer:

topjm [15]2 years ago

5 0

Answer:40.5

Step-by-step explanation:

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a jet climbs at a steady rate at an angle of inclination of 0.5 degrees during takeoff. What will its height be after a 2.2km in

Reil [10]

19.2m is the answer.

6 0

2 years ago

What dose this = to? triangles = to 180 buts all i know

lara31 [8.8K]

7. Straight lines are also = to 180°

If you look at the diagram, when you add the two angles together, they form a straight line.

Since the angles add up to 180°, you can do:

(x + 25)° + (4x + 5)° = 180°

x + 25 + 4x + 5 = 180 Combine like terms

5x + 30 = 180 Subtract 30 on both sides

5x = 150 Divide 5 on both sides

x = 30

3 0

3 years ago

9 inches of ribbon are needed for wrapping each present. How many presents can be wrapped with 6 yards of ribbon?

netineya [11]

Answer:

a total of 24 presents can be wrapped

Step-by-step explanation:

6 x 3 = 18 feet of ribbon

18 x 12 = 216 inches of ribbon

216/9 = 24 presents can be wrapped

3 0

2 years ago

find the volume of the solid formed by revolving the region bounded by the graphs of y = 4x - x^2 and f(x) = x^2 from [0,2] abou

Neko [114]

Answer:

$v = \frac{32\pi}{3}$

or

$v=33.52$

Step-by-step explanation:

Given

$f(x) = 4x - x^2$

$g(x) = x^2$

$[a,b] = [0,2]$

Required

The volume of the solid formed

Rotating about the x-axis.

Using the washer method to calculate the volume, we have:

$\int dv = \int\limit^b_a \pi(f(x)^2 - g(x)^2) dx$

Integrate

$v = \int\limit^b_a \pi(f(x)^2 - g(x)^2)\ dx$

$v = \pi \int\limit^b_a (f(x)^2 - g(x)^2)\ dx$

Substitute values for a, b, f(x) and g(x)

$v = \pi \int\limit^2_0 ((4x - x^2)^2 - (x^2)^2)\ dx$

Evaluate the exponents

$v = \pi \int\limit^2_0 (16x^2 - 4x^3 - 4x^3 + x^4 - x^4)\ dx$

Simplify like terms

$v = \pi \int\limit^2_0 (16x^2 - 8x^3 )\ dx$

Factor out 8

$v = 8\pi \int\limit^2_0 (2x^2 - x^3 )\ dx$

Integrate

$v = 8\pi [ \frac{2x^{2+1}}{2+1} - \frac{x^{3+1}}{3+1} ]|\limit^2_0$

$v = 8\pi [ \frac{2x^{3}}{3} - \frac{x^{4}}{4} ]|\limit^2_0$

Substitute 2 and 0 for x, respectively

$v = 8\pi ([ \frac{2*2^{3}}{3} - \frac{2^{4}}{4} ] - [ \frac{2*0^{3}}{3} - \frac{0^{4}}{4} ])$

$v = 8\pi ([ \frac{2*2^{3}}{3} - \frac{2^{4}}{4} ] - [ 0 - 0])$

$v = 8\pi [ \frac{2*2^{3}}{3} - \frac{2^{4}}{4} ]$

$v = 8\pi [ \frac{16}{3} - \frac{16}{4} ]$

Take LCM

$v = 8\pi [ \frac{16*4- 16 * 3}{12}]$

$v = 8\pi [ \frac{64- 48}{12}]$

$v = 8\pi * \frac{16}{12}$

Simplify

$v = 8\pi * \frac{4}{3}$

$v = \frac{32\pi}{3}$

or

$v=\frac{32}{3} * \frac{22}{7}$

$v=\frac{32*22}{3*7}$

$v=\frac{704}{21}$

$v=33.52$

8 0

3 years ago

Only need question 2

Elza [17]

Answer:

C- all numbers less than 13.

Why these are incorrect:

A- If it was "less than or equal to" the sign would have to be "≤"

B- If it was 'greater than or equal to" the sign would have to be "≥"

D- If it was "greater than" the sign would have to be ">"

4 0

3 years ago