Answer:
There will be 56 possible combinations if he is allowed to choose the same topping twice.
There will be 47 if he is not allowed to choose the same topping twice.
Step-by-step explanation:
So it's on 0-k on the number line
If it's opposite that i.e. to the right if zero, then 0+k
[4 - (3c - 1)][6 - (3c - 1)]
[4 - 3c + 1][6 - 3c + 1]
[-3c + 4 + 1][-3c + 6 + 1]
[-3c + 5][-3c + 7]
-3c[-3c + 7] + 5[-3c + 7]
-3c[-3c] - 3c[7] + 5[-3c] + 5[7]
9c² - 21c - 15c + 35
9c² - 36c + 35
