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Rama09 [41]
3 years ago
7

find the volume of the shaded solid. Round your answer to 2 decimal places if necessary. Use pi=3.14 when necessary. cylinder wi

th these 6ft, 18ft, 30 ft.

Mathematics
1 answer:
padilas [110]3 years ago
7 0
Ok so what we have is a large cylinder with a hollow cylindrical tube running thru the center. The volume of the shaded region should be the volume of the entire large cylinder (C) minus the volume of the small cylindrical tube (c): C - c
The volume of any cylinder is the area of the top circle (pi×r^2) times the height (h) of the cylinder, where r=radius of the circle. So: h×pi×r^2
The heights are the same for C and c, so we can call that h in both, which = 30ft. Now C's radius (R) = 1/2 of diameter, which is 18ft. So R = 9ft
c's radius (r) is 1/2 of its diameter, which is 6ft. So r = 3ft. Now we can set it up:
C - c = (h×pi×R^2) - (h×pi×r^2)
*since the h and pi in both formulae are multiplied by the other variable, we can factor that out:
h×pi(R^2) - h×pi(r^2) = h×pi(R^2-r^2)
h×pi = 30ft.×3.14 = 94.2ft. -->
94.2ft(9ft^2-3ft^2) = 94.2ft(81-9ft^2)
= 94.2ft(72ft^2) = 6782.4 ft.^3
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Step-by-step explanation:

We want to identify a rigid transformation that maps congruent triangles to one-another, to explain the coincidence of corresponding parts, and to identify the theorems that show congruence.

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<h3>1.</h3>

Triangles GBC and ABC share side BC. Whatever rigid transformation we use will leave segment BC invariant. Translation and rotation do not do that. The only possible transformation that will leave BC invariant is <em>reflection across line BC</em>.

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<h3>2.</h3>

In part 3, we show ∆GBC ≅ ∆ABC. That means vertices A and G are corresponding vertices. When we map the congruent figures onto each other, <em>corresponding parts are coincident</em>. That is, vertex G' (the image of vertex G) will coincide with vertex A.

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The markings on the figure show the corresponding parts to be ...

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There are four available congruence theorems applicable to triangles that are not right triangles

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We don't know which of these are in your notes, but we do know that all of them can be used. AAS can be used with two different sides. SAS can be used with two different angles.

SSS

  Corresponding sides are listed above. Here, we list them again:

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SAS

  One use is with AB, BC, and angle ABC corresponding to GB, BC, and angle GBC.

  Another use is with BA, AC, and angle BAC corresponding to BG, GC, and angle BGC.

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  Angles CAB and CBA, side AB corresponding to angles CGB and CBG, side GB.

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  One use is with angles CBA and CAB, side CB corresponding to angles CBG and CGB, side CB.

  Another use is with angles CBA and CAB, side CA corresponding to angles CBG and CGB, side CG.

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